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3 years ago

To find S, the number of shared

Chemistry

1 answer:

olasank [31]3 years ago

6 0

Answer:

I'm rly confused but Si stands for silicon in the compound if that's what ur asking

hope it helps tho

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Help please! + Brainliest

Anarel [89]

1.55 g/L; 9.503 03 × 10^20 mL

Part 1.

Step 1. Convert kilograms to grams.

1.55 kg × (1000 g/1 kg) = 1550 g

Step 2. Convert cubic metres to litres.

1 m^3 × (1000 L/1 m^3) = 1000 L

Step 3. Divide grams by litres

1.55 kg/1 m^3 = 1550 g/1000 L = 1.55 g/L

Part 2.

Step 1. Convert cubic kilometres to cubic metres

950 303 km^3 × (1000 m/1 km)^3 = 9.503 03 × 10^14 m^3

Step 2. Convert cubic metres to litres.

9.503 03 × 10^14 m^3 × (1000 L/1 m^3) = 9.503 03 × 10^17 L

Step 3. Convert litres to millilitres.

9.503 03 × 10^17 L × (1000 mL/1 mL) = 9.503 03 × 10^20 mL

8 0

4 years ago

List the five major pollutants in the United States

lawyer [7]

Fine particles, ground level ozone, sulfur dioxide, nitrogen dioxide, lead

6 0

4 years ago

magine that an uncharged pith ball is brought into the electrostatic field of a charged rod. The side of the pith ball closest t

ivanzaharov [21]

Answer: option D. be given a positive charge produced by the movement of electrons to the other end of the ball.


Explanation:

This phenomenon is called electrostatic induction.

The excess of negative charge on the end of the rod will repel the electrons on the side of the pith ball that have been approached to it.

Then the electrons on the pith ball will move far away from this end with it will be left an excess of positive charge.

In this way the rod has induced that the ball acquires a positive charge on one end and a negative charge on the other end.

4 0

3 years ago

Which group was fighting communists in Nicaragua in the 1980s?

stira [4]

The answer is A, the contras x Good luck!! :)

7 0

4 years ago

Silver sulfadiazine burn-treating cream creates a barrier against bacterial invasion and releases antimicrobial agents directly

trapecia [35]

Answer : The mass of silver sulfadiazine produced can be, 71.35 grams.

Solution : Given,

Mass of $Ag_2O$ = 25.0 g

Mass of $C_{10}H_{10}N_4SO_2$ = 50.0 g

Molar mass of $Ag_2O$ = 231.7 g/mole

Molar mass of $C_{10}H_{10}N_4SO_2$ = 250.3 g/mole

Molar mass of $AgC_{10}H_{9}N_4SO_2$ = 357.1 g/mole

First we have to calculate the moles of $Ag_2O$ and $C_{10}H_{10}N_4SO_2$ .

$\text{ Moles of }Ag_2O=\frac{\text{ Mass of }Ag_2O}{\text{ Molar mass of }Ag_2O}=\frac{25.0g}{231.7g/mole}=0.1079moles$

$\text{ Moles of }C_{10}H_{10}N_4SO_2=\frac{\text{ Mass of }C_{10}H_{10}N_4SO_2}{\text{ Molar mass of }C_{10}H_{10}N_4SO_2}=\frac{50.0g}{250.3g/mole}=0.1998moles$

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

$Ag_2O(s)+2C_{10}H_{10}N_4SO_2(s)\rightarrow 2AgC_{10}H_9N_4SO_2(s)+H_2O(l)$

From the balanced reaction we conclude that

As, 2 mole of $C_{10}H_{10}N_4SO_2$ react with 1 mole of $Ag_2O$

So, 0.1998 moles of $C_{10}H_{10}N_4SO_2$ react with $\frac{0.1998}{2}=0.0999$ moles of $Ag_2O$

From this we conclude that, $Ag_2O$ is an excess reagent because the given moles are greater than the required moles and $C_{10}H_{10}N_4SO_2$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of $AgC_{10}H_9N_4SO_2$

From the reaction, we conclude that

As, 2 mole of $C_{10}H_{10}N_4SO_2$ react with 2 mole of $AgC_{10}H_9N_4SO_2$

So, 0.1998 mole of $C_{10}H_{10}N_4SO_2$ react with 0.1998 mole of $AgC_{10}H_9N_4SO_2$

Now we have to calculate the mass of $AgC_{10}H_9N_4SO_2$

$\text{ Mass of }AgC_{10}H_9N_4SO_2=\text{ Moles of }AgC_{10}H_9N_4SO_2\times \text{ Molar mass of }AgC_{10}H_9N_4SO_2$

$\text{ Mass of }AgC_{10}H_9N_4SO_2=(0.1998moles)\times (357.1g/mole)=71.35g$

Therefore, the mass of silver sulfadiazine produced can be, 71.35 grams.

8 0

3 years ago