Answer:
The minimum molarity of acetic acid in vinegar according to given standards is 0.6660 mol/L.
Explanation:
4% acetic acid by mass means that 4 gram of acetic acid in 100 g solution.
Given that density of the vinegar is same is that of water = 1 g/mL
Mass of the vinegar solution = 100 g
Volume of the vinegar solution = V


V = 100 mL = 0.1 L
Moles of acetic acid =


The minimum molarity of acetic acid in vinegar according to given standards is 0.6660 mol/L.
Answer:
Explanation:
No not always but it is more likely they will
Answer:
I think its might be 1 because the ionic numbers for CA is +2 and for P its +3
Atomic mass (K)= 39.1 amu
therefore:
1 mol (k)---------------------39.1 g
x------------------------------- 2.25 g
x=(1 mol * 2.25 g) / 39.1 g=0.05754....≈0.06 moles
Answer: 0.06 moles.
The mass of an atom and the equivalent of to the number of protons and neutrons in the atom