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zubka84 [21]
3 years ago
14

Describe the two methods of active transport

Chemistry
2 answers:
OverLord2011 [107]3 years ago
6 0
Proteins in the Membrane. Active transport<span> usually happens across the cell membrane. ... They are positioned to cross the membrane so one part is on the inside of the cell and one part is on the outside. Only when they cross the bilayer are they able to move molecules and ions in and out of the cell.</span>
dimaraw [331]3 years ago
4 0
Endocytosis
Process by which the cell surrounds and takes particles into the cell

Exocytosis
Secretion of material out of the plasma membrane
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Chemistry! Help! Please!! Thanks
Vladimir79 [104]

Answers:

1. 3-ethyl-3-methylheptane; 2. 2,2,3,3-tetramethylpentane; 3. hexa-2,4-diene.

Explanation:

<em>Structure 1 </em>

  1. Identify and name the longest continuous chain of carbon atoms (the main chain has 7 C; ∴ base name = heptane).
  2. Identify and name all the substituents [a 1C substituent (methyl) and a 2C substituent (methyl).
  3. Number the main chain from the end closest to a substituent.
  4. Identify the substituents by the number of the C atom on the main chain. Use hyphens between letters and numbers (3-methyl, 3-ethyl).
  5. Put the names of the substituents in alphabetical order in front of the base name with no spaces (3-ethyl-3-methylheptane)

<em>Structure 2</em>

  1. 5C. Base name = pentane
  2. Four methyl groups.
  3. Number from the left-hand end.
  4. If there is more than one substituent of the same type, identify each substituent by its locating number and use a multiplying prefix to show the number of each substituent. Use commas between numbers (2,2,3,3-tetramethyl).
  5. The name is 2,2,3,3-tetramethylpentane.

<em>Structure 3 </em>

  1. Identify and name the longest continuous chain of carbon atoms that passes through as many double bonds as possible. Drop the <em>-ne</em> ending of the alkane to get the root name <em>hexa-</em>.
  2. (No substituents).
  3. Number the main chain from the end closest to a double bond.
  4. If there is more than one double bond use a multiplying prefix to indicate the number of double bonds (two double bonds = diene) and use the smaller of the two numbers of the C=C atoms as the double bond locators (2,4-diene)
  5. Put the functional group name at the end of the root name (hexa-2,4-diene).

<em>Note</em>: The name 2,4-hexadiene is <em>acceptable</em>, but the <em>Preferred IUPAC Name</em> puts the locating numbers as close as possible in front of the groups they locate.

7 0
3 years ago
Write out and BALANCE the following equation: Solid Scandium metal
Rama09 [41]
I need points thanks I need points thanks I need points thanks Wkbejwiwbwe e enjwkwkebe b a owl qiwi192928 Ake eleve
4 0
3 years ago
A chemist measures the amount of hydrogen gas produced during an experiment. She finds that 264. g of hydrogen gas is produced.
Lesechka [4]

Answer:

The answer is 130.953 g of hydrogen gas.

Explanation:

Hydrogen gas is formed by two atoms of hydrogen (H), so its molecular formula is H₂. We can calculate is molecular weight as the product of the molar mass of H (1.008 g/mol):

Molecular weight H₂= molar mass of H x 2= 1.008 g/mol x 2= 2.01568 g

Finally, we obtain the number of mol of H₂ there is in the produced gas mass (264 g) by using the molecular weight as follows:

mass= 264 g x 1 mol H₂/2.01568 g= 130.9731703 g

The final mass rounded to 3 significant digits is 130.973 g

4 0
3 years ago
1. Which statements represent properties of intermolecular forces? Select all that apply.
kumpel [21]

Answer:

C

Explanation:

Only this choice is applicable and correct.

The inter-molecular forces of attraction between the molecules must have been broken (overcome) before the molecules can gain an increase in the kinetic energies between them.

8 0
3 years ago
24 grams of iron is added to a graduated
Vanyuwa [196]

Answer:

d = 8 g/mL

Explanation:

Given data:

Mass of metal = 24 g

Volume of eater = 45 mL

Volume of water + metal = 48 mL

Density of iron metal = ?

Solution:

Volume of metal:

Volume of metal = volume of water+ metal - volume of water

Volume of metal = 48 mL - 45 mL

Volume of metal = 3 mL

Density of metal:

d = m/v

d = 24 g/ 3 mL

d = 8 g/mL

4 0
3 years ago
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