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4 years ago

Describe the two methods of active transport

2 answers:

OverLord2011 [107]4 years ago

6 0

Proteins in the Membrane. Active transport<span> usually happens across the cell membrane. ... They are positioned to cross the membrane so one part is on the inside of the cell and one part is on the outside. Only when they cross the bilayer are they able to move molecules and ions in and out of the cell.</span>

dimaraw [331]4 years ago

4 0

Endocytosis
Process by which the cell surrounds and takes particles into the cell

Exocytosis
Secretion of material out of the plasma membrane

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what happens to the rf value of your compound if you change your solvent from methylene chloride to methanol?

Masja [62]

Rf values may vary. Rf values vary depending on the material and solvent. The solvent that is used will alter the Rf value.

Rf values are typically higher for low polarity chemicals compared to higher polarity ones. Generally speaking, as polarity of a compound increases, so does its adsorptivity (i.e. the more polar the compound then the stronger it binds to the adsorbent). Solvents get more eluting as they become more polar.

The greater the compound's polarity, the more readily it will bind to the adsorbent, the closer it will come to the baseline, and the lower its Rf value. Many scientists use normal-phase flash chromatography with dichloromethane and methanol as the mobile phase to purify polar organic molecules. Due to methanol's high polarity and protic chemistry, it can frequently be difficult to optimize this solvent system.

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1 year ago

The reaction 2HgO (s)→2Hg (I)+O2 (g) has a percent yield of 50%. You want to produce 100 g of Hg.

nevsk [136]

The mass of HgO needed for the reaction is 216 g

The correct answer to the question is Option C. 216 g

We'll begin by calculating the theoretical yield of Hg.

Actual yield of Hg = 100 g

Percentage yield = 50%

Theoretical yield of Hg =?

Theoretical yield = Actual yield / percentage yield

Theoretical yield = 100 / 50%

Theoretical yield of Hg = 200 g

Finally, we shall determine the mass of HgO needed for the reaction.

2HgO → 2Hg + O₂

Molar mass of HgO = 201 + 16 = 217 g/mol

Mass of HgO from the balanced equation = 2 × 217 = 434 g

Molar mass of Hg = 201 g/mol

Mass of Hg from the balanced equation = 2 × 201 = 402 g

From the balanced equation above,

402 g of Hg were produced from 434 g of HgO.

Therefore

200 g of Hg will be produce by = (200 × 434) / 402 = 216 g of HgO.

Thus, 216 g of HgO is needed for the reaction.

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