1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Sonja [21]
3 years ago
9

13 Which pump is the most appropriate for low head high discharge capacity installations?

Engineering
1 answer:
gavmur [86]3 years ago
5 0

Options are missing and they are;

A. Propeller pump

B. Jet (mixed flow) pump

C. Centrifugal pump

D. Positive displacement pump

Answer:

C. Centrifugal pump

Explanation:

Dynamic pumps which are also known as centrifugal pumps are the ones widely used when we require high discharge. This is because they deal with transfer of fluids with low viscosity in flow rates that are high. Another reason is that they are also very good with low pressure installation.

You might be interested in
What is the tool used to take off a wheel nut
pishuonlain [190]

Answer:

A socket wrench

Explanation:

My dad is a mechanic

8 0
4 years ago
Read 2 more answers
Why the velocity potential Φ(x,y,z,t) exists only for irrotational flow
Black_prince [1.1K]

Answer:

\omega_y,\omega_x,\omega_Z  all are zero.

Explanation:

We know that if flow is possible then it will satisfy the below equation

\dfrac{\partial u}{\partial x}+\dfrac{\partial v}{\partial y}+\dfrac{\partial w}{\partial z}=0

Where u is the velocity of flow in the x-direction ,v is the velocity of flow in the y-direction and w is the velocity of flow in z-direction.

And velocity potential function \phi given as follows

 u=-\frac{\partial \phi }{\partial x},v=-\frac{\partial \phi }{\partial y},w=-\frac{\partial \phi }{\partial z}

Rotationality of fluid is given by \omega

\frac{\partial v}{\partial x}-\frac{\partial u}{\partial y}=\omega_Z

\frac{\partial v}{\partial z}-\frac{\partial w}{\partial y}=\omega_x

\frac{\partial w}{\partial x}-\frac{\partial u}{\partial z}=\omega_y

So now putting value in the above equations ,we will find

\omega =\frac{\partial \phi }{\partial x},u=\frac{\partial \phi }{\partial x},

\omega_y=\dfrac{\partial^2 \phi }{\partial z\partial x}-\dfrac{\partial^2 \phi }{\partial z\partial x}

So \omega_y=0

Like this all \omega_y,\omega_x,\omega_Z all are zero.

That is why  velocity potential flow is irroational flow.

5 0
4 years ago
What is reciprocity?
Murrr4er [49]

Answer:

the practice of exchanging things with others for mutual benefit, especially privileges granted by one country or organization to another.

HOPE THIS HELPED!!!!!!!!!!!!! XDDDDDD

7 0
4 years ago
Read 2 more answers
A square steel bar has a length of 7.2 ft and a 2.5 in by 2.5 in cross section and is subjected to axial tension. The final leng
Nataly_w [17]

Answer:

A) ν = 0.292

B) ν = 0.381

Explanation:

Poisson's ratio = - (Strain in the direction of the load)/(strain in the direction at right angle to the load)

In axial tension, the direction of the load is in the length's direction and the direction at right angle to the load is the side length

Strain = change in length/original length = (Δy)/y or (Δx)/x or (ΔL/L)

A) Strain in the direction of the load = (2.49946 - 2.5)/2.5 = - 0.000216

Strain in the direction at right angle to the load = (7.20532 - 7.2)/7.2 = 0.0007389

Poisson's ratio = - (-0.000216)/(0.0007389) = 0.292

B) Strain in the direction of the load = (2.09929 - 2.1)/2.1 = - 0.0003381

Strain in the direction at right angle to the load = (5.30470 - 5.3)/5.3 = 0.0008868

Poisson's ratio = - (-0.0003381)/(0.0008868) = 0.381

7 0
3 years ago
Two concentric helical compression springs made of steel and having the same length when loaded and when unloaded are used to su
Andrews [41]

Answer:

see explaination for all the answers and full working.

Explanation:

deflection=8P*DN/Gd^4

G(for steel)=70Gpa=70*10^9N/m^2=70KN/mm^2

for outer spring,

deflection=8*3*50^3*5/(70*9^4)=32.66mm

for inner spring

deflection=8*3*30^3*10/(70*5^4)=148.11mm

max stress=k*8*P*C/(3.14*d^2)

for outer spring

c=50/9=5.55

k=(4c-1/4c-4)+.615/c=1.2768

max stress=1.2768*8*3*5.55/(3.14*9^2=.66KN.mm^2

for inner spring

c=6

k=1.2525

max stress=2.29KN/mm^2

6 0
4 years ago
Read 2 more answers
Other questions:
  • Snoopy is inflated for the Macy’s Thanksgiving parade with 50,000 L of He at 25 oC and 1.2 atm. What is the percent decrease in
    15·1 answer
  • Ammonia enters the expansion valve of a refrigeration system a temperature of 24oC and pressure of10 bar and exits at 1 bar. If
    12·1 answer
  • 2. The soil borrow material to be used to construct a highway embankment has a mass unit weight of 110.0 pcf, a water content of
    11·1 answer
  • Heating of Oil by Air. A flow of 2200 lbm/h of hydrocarbon oil at 100°F enters a heat exchanger, where it is heated to 150°F by
    7·1 answer
  • List 3 appliances each of the following<br>soil<br>waste​
    7·1 answer
  • Distinguish between systems analysis and systems design?
    12·1 answer
  • What is the answer???
    10·1 answer
  • The demand for Manufacturing jobs is O decreasing O increasing O slowly changing. O remaining constant.​
    6·2 answers
  • An unknown relative passes away and bequeaths upon you a small tract of land in Amherst. You decide to build a two-story storage
    14·1 answer
  • Write the design brief (identify the problem) of mine headgear​
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!