Answer:
For
- 5.556 lb/s
For
- 7.4047 lb/s
Solution:
As per the question:
System Load = 96000 Btuh
Temperature, T = ![20^{\circ}](https://tex.z-dn.net/?f=20%5E%7B%5Ccirc%7D)
Temperature rise, T' =
Now,
The system load is taken to be at constant pressure, then:
Specific heat of air, ![C_{p} = 0.24 btu/lb ^{\circ}F](https://tex.z-dn.net/?f=C_%7Bp%7D%20%3D%200.24%20btu%2Flb%20%5E%7B%5Ccirc%7DF)
Now, for a rise of
in temeprature:
![\dot{m}C_{p}\Delta T = 96000](https://tex.z-dn.net/?f=%5Cdot%7Bm%7DC_%7Bp%7D%5CDelta%20T%20%3D%2096000)
![\dot{m} = \frac{96000}{C_{p}\Delta T} = \frac{96000}{0.24\times 20} = 20000 lb/h = \frac{20000}{3600} = 5.556 lb/s](https://tex.z-dn.net/?f=%5Cdot%7Bm%7D%20%3D%20%5Cfrac%7B96000%7D%7BC_%7Bp%7D%5CDelta%20T%7D%20%3D%20%5Cfrac%7B96000%7D%7B0.24%5Ctimes%2020%7D%20%3D%2020000%20lb%2Fh%20%3D%20%5Cfrac%7B20000%7D%7B3600%7D%20%3D%205.556%20lb%2Fs)
Now, for
:
![\dot{m}C_{p}\Delta T = 96000](https://tex.z-dn.net/?f=%5Cdot%7Bm%7DC_%7Bp%7D%5CDelta%20T%20%3D%2096000)
![\dot{m} = \frac{96000}{C_{p}\Delta T} = \frac{96000}{0.24\times 15} = 26666.667 lb/h = \frac{26666.667}{3600} = 7.4074 lb/s](https://tex.z-dn.net/?f=%5Cdot%7Bm%7D%20%3D%20%5Cfrac%7B96000%7D%7BC_%7Bp%7D%5CDelta%20T%7D%20%3D%20%5Cfrac%7B96000%7D%7B0.24%5Ctimes%2015%7D%20%3D%2026666.667%20lb%2Fh%20%3D%20%5Cfrac%7B26666.667%7D%7B3600%7D%20%3D%207.4074%20lb%2Fs)
Answer:
Atlantis benefited from lessons learned in the construction and testing of Enterprise, Columbia and Challenger. ... The Experience gained during the Orbiter assembly process also enabled Atlantis to be completed with a 49.5 percent reduction in man hours (compared to Columbia).
Explanation:
Answer:
Heat transfer rate(Q)= 1.197kW
Power output(W)=68.803kW
I think the answer is B. 10D
Answer:
Explained
Explanation:
Cold working: It is plastic deformation of material at temperature below recrystallization temperature. whereas hot working is deforming material above the recrystallization temperature.
Given melting point temp of lead is 327° C and lead recrystallizes at about
0.3 to 0.5 times melting temperature which will be higher that 20°C. Hence we can conclude that at 20°C lead will under go cold working only.