Answer:
hole at x=-3
Step-by-step explanation:
The hole is the discontinuity that exists after the fraction reduces. (Still doesn't exist for original of course)
The discontinuities for this expression is when the bottom is 0. x^2-9=0 when x=3 or x=-3 since squaring either and then subtracting 9 would lead to 0.
So anyways we have (x+3)/(x^2-9)
= (x+3)/((x-3)(x+3))
Now this equals 1/(x-3) with a hole at x=-3 since the x+3 factor was "cancelled" from the denominator.
Answer:
It's A
Step-by-step explanation:
would u like me to explain it??
You are multiplying by 3 each time. This sequence is geometric.
9 = 3*3 = 3^2
27 = 3*9 = 3*3*3 = 3^3
81 = 3*27 = 3*3*3*3 = 3^4
and so on.
The general rule is 3^x which is choice D
