Answer:
t=5.5080( to 3 d.p)
Step-by-step explanation:
From the data given,
n =20
Deviation= 34/20= 1.7
Standard deviation (sd)= 1.3803(√Deviation)
Standard Error = sd/√n
= 1.3803/V20 = 0.3086
Test statistic is:
t = deviation /SE
= 1.7/0.3086 = 5.5080
ndf = 20 - 1 = 19
alpha = 0.01
One Tailed - Right Side Test
From Table, critical value of t =2.5395
Since the calculated value of t = 5.5080 is greater than critical value of t = 2.5395, the difference is significant. Reject null hypothesis.
t score = 5.5080
ndf = 19
One Tail - Right side Test
By Technology, p - value = 0.000
Since p - value is less than alpha , reject null hypothesis.
Conclusion:
From the result obtained it can be concluded that ,the data support the claim that the mean rating assigned to the wine when the cost is described as $90 is greater than the mean rating assigned to the wine when the cost is described as $10.
What tray..there is not enough information to help you
Answer:
7
Step-by-step explanation:
28 35 56
1 and 28 1 and 35 1 and 56
2 and 14 7 and 5 2 and 28
4 and 7 4 and 14
7 and 8
Answer:
The percentage decrease of the number of visitors to Alec's website from February to March is 14.8 %
Step-by-step explanation:
Explanation:
Percent decrease is a measure of percent change, which is the extent to which something loses value.
Step 1:
Find out the difference (decrease) between the number of visitors in march and February
Decrease =number of visitors in Fe bury- Number of vsitors in march
Decrease= 1,586- 1,352
Decrease =234
Step 2:
Divide the decrease by the original number of visitors and multiply the answer by 100.
Percent decrease= 
Percent decrease= 
Percent decrease= 
Percent decrease =14.88
