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Georgia [21]
3 years ago
14

For a nozzle-duct system shown in Fig Q3, the nozzle is designed to produce a Mach number of 2.8 with y = 1.4, The inlet conditi

ons are pos= 10 bar and T = 370 K. The duct is 8 diameters in length, but the duct friction factor is unknown. The receiver pressure is fixed at 3 bar and a normal shock has formed at the duct exit.<br /><br />(a) Determine the friction factor of the duct. (b) What is the total change in entropy for the system?​
Engineering
1 answer:
Studentka2010 [4]3 years ago
5 0

Answer:

it's really hearts:< SEND ANSWER GUYZ HALABUALL;> <em>BY</em><em> </em><em>DA</em><em> </em><em>WAY</em><em> </em><em>GUD</em><em> </em><em>EVENING</em>

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A machine raises 20kg of water through a height of 50m in 10secs. What is the power of the machine.​
Tomtit [17]

Answer:

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Explanation:

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5 0
3 years ago
Consider a resistor made of pure silicon with a cross-sectional area pf 0.5 μm2, and a length of 50 μm. What is the resistance o
lukranit [14]

Answer: 24 pA

Explanation:

As pure silicon is a semiconductor, the resistivity value is strongly dependent of temperature, as the main responsible for conductivity, the number of charge carriers (both electrons and holes) does.

Based on these considerations, we found that at room temperature, pure silicon resistivity can be approximated as 2.1. 10⁵  Ω  cm.

The resistance R of a given resistor, is expressed by the following formula:

R = ρ L / A

Replacing by the values for resistivity, L and A, we have

R = 2.1. 10⁵ Ω  cm. (10⁴ μm/cm). 50 μm/ 0.5 μm2

R = 2.1. 10¹¹ Ω

Assuming that we can apply Ohm´s Law, the current that would pass through this resistor for an applied voltage of 5 V, is as follows:

I = V/R = 5 V / 2.1.10¹¹ Ω = 2.38. 10⁻¹¹ A= 24 pA

7 0
3 years ago
A program is seeded with 30 faults. During testing, 21 faults are detected, 15 of which are seeded faults and 6 of which are ind
Vesna [10]

Answer:

Estimated number of indigenous faults remaining undetected is 6

Explanation:

The maximum likelihood estimate of indigenous faults is given by,

N_F=n_F\times \frac{N_S}{n_S} here,

n_F = the number of unseeded faults = 6

N_S = number of seeded faults = 30

n_s = number of seeded faults found = 15

So NF will be calculated as,

N_F=6\times \frac{30}{15}=12

And the estimate of faults remaining is  N_F-n_F = 12 - 6 = 6

8 0
3 years ago
Out
olchik [2.2K]

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3 years ago
Phil wants to make a dark themed superhero movie. What could be his target demographic?
grin007 [14]

Answer:

D.

male, aged 18-25

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3 years ago
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