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snow_lady [41]
3 years ago
6

A composite wall consists of 20 mm thick steel plate backed by insulation brick (k = 0.39 W/mK) of 50 cm thickness and overlaid

by mineral wool of 20 cm thickness (k = 0.05 W/mK) and 70 cm layer of brick of (k = 0.39 W/mK). The inside is exposed to convection at 650°C with h = 65 W/ m2K. The outside is exposed to air at 35°C with a convection coefficient of 15 W/m2K. Determine the heat loss per unit area, interface temperatures and temperature gradients in each materials.

Engineering
1 answer:
jeyben [28]3 years ago
6 0

Answer:

Heat loss=85.9W/m^2

ΔT1(Steel)=0.04C

ΔT2(Brick1)=110.13C

ΔT3(Mwood)=343.6C

ΔT1(Brick2)=154.18C

Explanation:

raise the heat transfer equation from the air inside the wall to the outside air from the wall, because that is where you have the temperature data, to find the heat.

To find the temperatures you use the heat found in the previous step, and you use the conduction and convection equations in each wall layer.

I attached the procedure

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From the given info, we can write an expression and solve it:

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Now we have 2 equations, we can use them to solve using whatever method you want.

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I will be using matrices RREF to solve for this.

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