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2 years ago

What is the role a species can assume in an ecosystem?

Chemistry

1 answer:

RSB [31]2 years ago

4 0

Answer:

A niche is the role a species plays in the ecosystem. In other words, a niche is how an organism “makes a living.” A niche will include the organism's role in the flow of energy through the ecosystem.

Explanation:

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What is the "reproductive system"

bija089 [108]

Answer: The reproductive system of an organism, also known as the genital system, is the biological system made up of all the anatomical organs involved in sexual reproduction

OMG LOL

6 0

2 years ago

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Some SbCl5 is allowed to dissociate into SbCl3 and Cl2 at 521 K. At equilibrium, [SbCl5] = 0.195 M, and [SbCl3] = [Cl2] = 6.98×1

Brilliant_brown [7]

Answer:

a) The equilibrium will shift in the right direction.

b) The new equilibrium concentrations after reestablishment of the equilibrium :

$[SbCl_5]=(0.370-x) M=(0.370-0.0233) M=0.3467 M$

$[SbCl_3]=(6.98\times 10^{-2}+x) M=(6.98\times 10^{-2}+0.0233) M=0.0931 M$

$[Cl_2]=(6.98\times 10^{-2}+x) M=(6.98\times 10^{-2}+0.0233) M=0.0931 M$

Explanation:

$SbCl_5(g)\rightleftharpoons SbCl_3(g) + Cl_2(g)$

a) Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.

This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.

On increase in amount of reactant

$SbCl_5(g)\rightleftharpoons SbCl_3(g) + Cl_2(g)$

If the reactant is increased, according to the Le-Chatlier's principle, the equilibrium will shift in the direction where more product formation is taking place. As the number of moles of $SbCl_5$ is increasing .So, the equilibrium will shift in the right direction.

$SbCl_5(g)\rightleftharpoons SbCl_3(g) + Cl_2(g)$

Concentration of $SbCl_5$ = 0.195 M

Concentration of $SbCl_3$ = $6.98\times 10^{-2} M$

Concentration of $Cl_2$ = $6.98\times 10^{-2} M$

On adding more $[SbCl_5$ to 0.370 M at equilibrium :

$SbCl_5(g)\rightleftharpoons SbCl_3(g) + Cl_2(g)$

Initially

0.370 M $6.98\times 10^{-2}M$

At equilibrium:

(0.370-x)M $(6.98\times 10^{-2}+x)M$

The equilibrium constant of the reaction = $K_c$

$K_c=2.50\times 10^{-2}$

The equilibrium expression is given as:

$K_c=\frac{[SbCl_3][Cl_2]}{[SbCl_5]}$

$2.50\times 10^{-2}=\frac{(6.98\times 10^{-2}+x)M\times (6.98\times 10^{-2}+x)M}{(0.370-x) M}$

On solving for x:

x = 0.0233 M

The new equilibrium concentrations after reestablishment of the equilibrium :

$[SbCl_5]=(0.370-x) M=(0.370-0.0233) M=0.3467 M$

$[SbCl_3]=(6.98\times 10^{-2}+x) M=(6.98\times 10^{-2}+0.0233) M=0.0931 M$

$[Cl_2]=(6.98\times 10^{-2}+x) M=(6.98\times 10^{-2}+0.0233) M=0.0931 M$

3 0

3 years ago

Which type of reaction occurs in the following equation?

Tema [17]

The type of reaction which occurs is referred to as redox reaction. This kind of reaction involve both oxidation and reduction.
Al(s) is oxidized to alluminium ions, while cu2+ is reduced copper metal.Reduction occurs at the cathode while oxidation occurs at the anode.

3 0

3 years ago

Read 2 more answers

I’ll give the Brainliest

Bond [772]

Answer:

D. is the Answer. ✅

Explanation:

The Moon is 1/4 the size of Earth.

A is not right because Moon isn't a dwarf planet.❌

B is not right because the Moon isn't 1/2 the size of Earth.❌

C is not right because the Moon is no where near as large as Earth.❌

5 0

2 years ago

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In the reaction Fe2O3 + 3CO a 2Fe + 3CO2, 10 moles of solid iron and 15 moles of carbon dioxide are produced from 5 moles of iro

Schach [20]

Answer:

Ratio is 3:2

3CO = 2Fe or 1.5 CO = 1 Fe

Explanation:

Fe2O3 + 3CO = 2Fe + 3CO2

Fe2O3 = Iron (|||) oxide

CO = Carbon monoxide

Fe = Solid Iron

CO2 = Carbon dioxide

Excellent is already balanced.

10 Moles Fe and 15 Moles of CO2

5 Moles Fe2O3 + 15 Moles 3CO = 10 Moles Fe + 15 Moles 3CO2

What is the ratio of carbon monoxide to solid iron

Ratio is 3:2 or 1.5 CO = 1 Fe

5 0

3 years ago