Answer:
Magnitude of fourth displacement is approximately 95 metres,
Direction of fourth displacement is straight west.
The velocity of the boy when he hits the water at the bottom of the slide is 14 m/s.
<h3>
Velocity of the boy at the bottom of the slide</h3>
The velocity of the boy when he hits the water at the bottom of the slide is calculated from the principle of conservation of energy.
K.E = P.E
¹/₂mv² = mgh
v² = 2gh
v = √2gh
where;
- h is height of the boy
- g is acceleration due to gravity
v = √(2 x 9.8 x 10)
v = 14 m/s.
Thus, the velocity of the boy when he hits the water at the bottom of the slide is 14 m/s.
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Answer:
And for this case we can write this expression like this:
The velocity would be given by the first derivate and we got:
And the maximum velocity would be:
Explanation:
For this case we have the following function for the position:
And for this case we can write this expression like this:
The velocity would be given by the first derivate and we got:
And the maximum velocity would be:
Answer:
Geometrical representation
Explanation:
neglecting air resistance both will land at the same moment.
both have therefore the same acceleration.