(a) The object moves with uniform velocity from A to B.
(b) The object moves with constant velocity from B to C.
(c) The object moves with increasing velocity from C to D.
<h3>
Velocity of the object from point A to B</h3>
V(A to B) = (6 - 0)/(4 - 0) = 1.5 m/s
<h3>
Velocity of the object from point B to C</h3>
V(B to C) = (6 - 6)/(11 - 4) = 0 m/s
<h3>
Velocity of the object from point C to D</h3>
V(C to D) = (7 - 6)/(12 - 11) = 1 m/s
final velocity = 1 + 1.5 m/s = 2.5 m/s
Thus, we can conclude the following;
The object moves with uniform velocity from A to B.
The object moves with constant velocity from B to C.
The object moves with increasing velocity from C to D.
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Answer:
The horse father from the center has a greater tangential speed. Although both horses complete one circle in the same time period, the one farther from the center covers a greater distance during that same period.
Explanation:
<span>
be aware of large trucks on the roadway
Tip: usually, these signs are hazard signs or warning.
Also, this isnt physics </span><span />
<span>The law of conservation of matter and energy relates to the cycles in nature, and by that it is also applied to rocks and other materials. All of the rock in the Earth is recycled and accounted for during the rock cycle. Rocks experience physical change, the composition of the material stays the same, it may just change how it looks and chemical changes occur (the suubstance undergoes a chemical reaction that changes the actual makeup of the substance).</span>
Answer:

Explanation:
We have an uniformly accelerated motion, with a negative acceleration. Thus, we use the kinematic equations to calculate the distance will it take to bring the car to a stop:

The acceleration can be calculated using Newton's second law:

Recall that the maximum force of friction is defined as
. So, replacing this:

Now, we calculate the distance:
