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Mnenie [13.5K]
3 years ago
6

Pushing a baby on a swing is easier than pushing an adult on the same swing.

Physics
2 answers:
Shalnov [3]3 years ago
7 0

Answer:

Law 2:

Pushing a baby on a swing is easier than pushing an adult on the same swing. Water spills from a glass carried by someone who is walking steadily and suddenly stops short.

Law 2:

When thrown with the same force, a soccer ball accelerates more than a bowling ball.

Law 1:

A magician pulls a tablecloth out from under a dish on a table without disturbing the dish.

Law 3:

A rocket launches into space, pushing fuel exhaust in one direction and the rocket in the opposite direction.

Law 1:

A book rests on top of a shelf and does not move until a student accidentally knocks it off.

Explanation:

Newton's laws of motion:

Law 1: Law of inertia

Law 2: Law of force (F = mass x acceleration)

Law 3: Law of Action & Reaction

Sergeeva-Olga [200]3 years ago
5 0

Answer:

what is the question though

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If the Sun were the size of a small exercise ball (about 0.5 meters (m) in
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the size of a pea

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How are Newton's 3 laws related?
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A person sitting on a pier observes incoming waves that have a sinusoidal form with a distance of 2.5 m between the crests. Of a
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Answer:

Part(a): The frequency is \bf{0.2~Hz}.

Part(b): The speed of the wave is \bf{0.5~m/s}.

Explanation:

Given:

The distance between the crests of the wave, d = 2.5~m.

The time required for the wave to laps against the pier, t = 5.0~s

The distance between any two crests of a wave is known as the wavelength of the wave. So the wavelength of the wave is \lambda = 2.5~m.

Also, the time required for the wave for each laps is the time period of oscillation and it is given by T = 5.0~s.

Part(a):

The relation between the frequency and time period is given by

\nu = \dfrac{1}{T}~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(1)

Substituting the value of T in equation (1), we have

\nu &=& \dfrac{1}{5.0~s}\\~~~&=& 0.2~Hz

Part(b):

The relation between the velocity of a wave to its frequency is given by

v = \nu \lambda~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(2)

Substituting the value of \nu and \lambda in equation (2), we have

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