Answer:
Step-by-step explanation:
this isn’t an answer but did u did the answer to this because i need it. thanks
Answer:
Part 1) 
Part 2) 
Part 3) 
Part 4) 
Part 5) 
Part 6) 
Step-by-step explanation:
Part 1) we know that
The shaded region is equal to the area of the complete rectangle minus the area of the interior rectangle
The area of rectangle is equal to
where
b is the base of rectangle
h is the height of rectangle
so
Part 2) we know that
The shaded region is equal to the area of the complete rectangle minus the area of the interior square
The area of square is equal to
where
b is the length side of the square
so
Part 3) we know that
The area of the shaded region is equal to the area of four rectangles plus the area of one square
so
Part 4) we know that
The shaded region is equal to the area of the complete square minus the area of the interior square
so
Part 5) we know that
The area of the shaded region is equal to the area of triangle minus the area of rectangle
The area of triangle is equal to
where
b is the base of triangle
h is the height of triangle
so
Part 6) we know that
The area of the shaded region is equal to the area of the circle minus the area of rectangle
The area of the circle is equal to
where
r is the radius of the circle
so
Answer:
The answer is 5/6.
Step-by-step explanation:
Lets start with a=1.
a+1=2, which is the denominator. (1/2)
Taking the same number as numerator, now, consider a=2.
a+1=3, denominator.(2/3)
Now, let a=3.
a+1==4, denominator for a=3. (3/4)
If continued a becomes equal to 4.
a+1=5, which is also the denominator. (4/5)
Now, since the denominator is 5, let a=5.
a+1=6, which will become the denominator. (5/6)
Thus the series follows a pattern of a/a+1.
Answer: D
Step-by-step explanation:
Consider the first equation. Subtract 3x from both sides.
y−3x=−2
Consider the second equation. Subtract x from both sides.
y−2−x=0
Add 2 to both sides. Anything plus zero gives itself.
y−x=2
To solve a pair of equations using substitution, first solve one of the equations for one of the variables. Then substitute the result for that variable in the other equation.
y−3x=−2,y−x=2
Choose one of the equations and solve it for y by isolating y on the left hand side of the equal sign.
y−3x=−2
Add 3x to both sides of the equation.
y=3x−2
Substitute 3x−2 for y in the other equation, y−x=2.
3x−2−x=2
Add 3x to −x.
2x−2=2
Add 2 to both sides of the equation.
2x=4
Divide both sides by 2.
x=2
Substitute 2 for x in y=3x−2. Because the resulting equation contains only one variable, you can solve for y directly.
y=3×2−2
Multiply 3 times 2.
y=6−2
Add −2 to 6.
y=4
The system is now solved.
y=4,x=2
One number is 4
Another is 2 I hope this helped
