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AlladinOne [14]
3 years ago
11

The probability of rolling an odd number with a six-sided number cube is 1/2 Choose the likelihood that best describes the proba

bility of this event.
O A. Unlikely
O B. Likely
O C. Certain
O D. Neither likely nor unlikely​
Mathematics
1 answer:
Ket [755]3 years ago
8 0

Answer:

D. Neither likely not unlikely

Step-by-step explanation:

APX approved

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1. Which of the following describes an argument based on the idea that if you have a few cases, you can draw a conclusion?
cluponka [151]

Answer:

B. Limited choice

3 0
3 years ago
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A tablet PC contains 3217 music files. The distribution of file size is highly skewed with many small files. Suppose the true me
m_a_m_a [10]

Answer:

Let X the random variable who represents the file sizeof music. We know the following info:

\mu =2.3,\sigma =3.25

We select a sample of n=50 nails. That represent the sample size.  

Since the sample size is large enough n >30, we can use the central limit theorem. From this theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we can approximate the distribution of the sample mean as a normal distribution and no matter if the distribution for X is right skewed or no.

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Let X the random variable who represents the file sizeof music. We know the following info:

\mu =2.3,\sigma =3.25

We select a sample of n=50 nails. That represent the sample size.  

Since the sample size is large enough n >30, we can use the central limit theorem. From this theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we can approximate the distribution of the sample mean as a normal distribution and no matter if the distribution for X is right skewed or no.

8 0
3 years ago
Dividing Mixed fractions
Komok [63]
First you would make the mixed fractions into improper fraction by multiplying the denominator and the whole number, then adding the numerator. Then you would flip the second fraction and multiply. 
Ex. 1 1/2 ÷1 1/2
1st. 3/2÷3/2
2nd: 3/2×2/3
3rd 3/2x2/3=1
6 0
3 years ago
During the first part of a​ trip, a canoeist travels 18 miles at a certain speed. the canoeist travels 4 miles on the second par
storchak [24]
We can set it up like this, where <em>s </em>is the speed of the canoeist:

\frac{18}{s} + \frac{4}{s-5} = 3

To make a common denominator between the fractions, we can multiply the whole equation by s(s-5):

s(s-5)[\frac{18}{s} + \frac{4}{s-5} = 3] \\ 18(s-5)+4s=3s(s-5) \\ 18s - 90+4s=3 s^{2} -15s

If we rearrange this, we can turn it into a quadratic equation and factor:

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Technically, either of these solutions would work when plugged into the original equation, but I would use the second solution because it's a little "neater."  We have the speed for the first part of the trip (9 mph); now we just need to subtract 5mph to get the speed for the second part of the trip.

9-5 = 4

The canoeist's speed on the first part of the trip was 9mph, and their speed on the second part was 4mph.
5 0
3 years ago
Can you guys help me match the transformations with there deception.
pishuonlain [190]

Answer:

1,3 2,2 3,4 4,1

Step-by-step explanation:

6 0
3 years ago
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