A number is chosen at random from 1 to 50. Find the probability of selecting numbers less than 33

What is 10 x 5 + 9 - 8 i need this right now

sveta [45]

Answer:

51

Step-by-step explanation:

10 by 5 is 50 plus 9 is 59 subtract 8 is 51

10*5+9-8 = 51

8 0

3 years ago

The construction method used to construct a perpendicular through a point not on a line could also be used to construct a perpen

Rama09 [41]

The answer for the question above is TRUE.

Given a line segment with endpoints A and B, we must merely find a point on the perpendicular bisector of the line AB, then use the perpendicular line construction. To find the point on the perpendicular bisector, we must merely find a point that is equidistant from both A and B. We can do this with a compass by choosing a compass length greater than half the length AB, and then making an arc from A above the line AB. Then we make an arc from B having the same length.

Since we used the same length for each arc, the intersection of the arcs, P, is equidistant from A and B. Now we simply use the perpendicular line construction for line AB and P, which is off the line. This line will be a perpendicular bisector.

6 0

3 years ago

Identify the variable expression that is not a polynomial. A.Y+1 B. C.x^12 D.23

dolphi86 [110]

A polynomial is consisting of several terms so D.23

7 0

3 years ago

The operations manager of a manufacturer of television remote controls wants to determine which batteries last the longest in hi

Gnom [1K]

Answer:

There is not enough evidence to support the claim that the longevity of the two brand of batteries differs.

Step-by-step explanation:

The question is incomplete:

The sample data for each battery is:

Battery 1: 106 111 109 105

Battery 2: 125 103 121 118

The mean and STD for the sample of battery 1 are:

$M_1=\dfrac{1}{4}\sum_{i=1}^{4}(106+111+109+105)\\\\\\ M_1=\dfrac{431}{4}=107.75$

$s_1=\sqrt{\dfrac{1}{(n-1)}\sum_{i=1}^{4}(x_i-M)^2}\\\\\\s_1=\sqrt{\dfrac{1}{3}\cdot [(106-(107.75))^2+(111-(107.75))^2+(109-(107.75))^2+(105-(107.75))^2]}\\\\\\ s_1=\sqrt{\dfrac{1}{3}\cdot [(3.06)+(10.56)+(1.56)+(7.56)]}\\\\\\ s_1=\sqrt{\dfrac{22.75}{3}}=\sqrt{7.58333333333333}\\\\\\s_1=2.754$

The mean and STD for the sample of battery 2 are:

$M_2=\dfrac{1}{4}\sum_{i=1}^{4}(125+103+121+118)\\\\\\ M_2=\dfrac{467}{4}=116.75$

$s_2=\sqrt{\dfrac{1}{(n-1)}\sum_{i=1}^{4}(x_i-M)^2}\\\\\\s_2=\sqrt{\dfrac{1}{3}\cdot [(125-(116.75))^2+(103-(116.75))^2+(121-(116.75))^2+(118-(116.75))^2]}\\\\\\ s_2=\sqrt{\dfrac{1}{3}\cdot [(68.06)+(189.06)+(18.06)+(1.56)]}\\\\\\ s_2=\sqrt{\dfrac{276.75}{3}}=\sqrt{92.25}\\\\\\s_2=9.605$

This is a hypothesis test for the difference between populations means.

The claim is that the longevity of the two brand of batteries differs.

Then, the null and alternative hypothesis are:

$H_0: \mu_1-\mu_2=0\\\\H_a:\mu_1-\mu_2\neq 0$

The significance level is α=0.05.

The sample 1, of size n1=4 has a mean of 107.75 and a standard deviation of 2.754.

The sample 2, of size n2=4 has a mean of 116.75 and a standard deviation of 9.605.

The difference between sample means is Md=-9.

$M_d=M_1-M_2=107.75-116.75=-9$

The estimated standard error of the difference between means is computed using the formula:

$s_{M_d}=\sqrt{\dfrac{\sigma_1^2+\sigma_2^2}{n}}=\sqrt{\dfrac{2.754^2+9.605^2}{4}}\\\\\\s_{M_d}=\sqrt{\dfrac{99.841}{4}}=\sqrt{24.96}=4.996$

Then, we can calculate the t-statistic as:

$t=\dfrac{M_d-(\mu_1-\mu_2)}{s_{M_d}}=\dfrac{-9-0}{4.996}=\dfrac{-9}{4.996}=-1.8014$

The degrees of freedom for this test are:

$df=n_1+n_2-1=4+4-2=6$

This test is a two-tailed test, with 6 degrees of freedom and t=-1.8014, so the P-value for this test is calculated as (using a t-table):

$P-value=2\cdot P(t$

As the P-value (0.122) is greater than the significance level (0.05), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the longevity of the two brand of batteries differs.

5 0

3 years ago

Q20. A sample of 900 students found that the average time spent studying was 1.3 hours on average with a standard

allochka39001 [22]

Answer:

B

Step-by-step explanation:

3 0

2 years ago