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den301095 [7]
3 years ago
5

A car moving south speeds up from 10 m/s to 40 m/s in 15 seconds. What is the car’s acceleration? A. 2 m/s2 B.15 m/s2 C.30 m/s2

D.50 m/s2
Physics
2 answers:
Ainat [17]3 years ago
6 0
A. 2 m/s^2

40-10=30
30÷15 =2
Black_prince [1.1K]3 years ago
5 0

Answer:

Acceleration, a=2\ m/s^2

Explanation:

It is given that,

A car moving south speeds up from 10 m/s to 40 m/s in 15 seconds.

It means,

Initial velocity of the car, u = 10 m/s

Final velocity of the car, v = 40 m/s

Time taken, t = 15 seconds

We have to find the acceleration of the car. Mathematically, acceleration of the car is given by taking difference in velocities divided by time taken i.e.

a=\dfrac{v-u}{t}

a=\dfrac{40\ m/s-10\ m/s}{15\ s}

a=2\ m/s^2

Hence, this is the required solution.

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The table below shows the right ascensions of two stars at a location.
noname [10]
Star 1 - 4 hours right ascension
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 Subtracting hours right ascension
 4 hours right ascension - 3 hours right ascension = 1 hours right ascension.
Thus,
 star 1 will rise 1 hour before star 2
7 0
3 years ago
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A sample contains 36 g of a radioactive isotope. How much radioactive isotope remains in the sample after 3 half-lives?
Gre4nikov [31]

Answer:

<u>Option "C":</u> "4.5 g"

Explanation:

N0 = 36 g, Let half-life is T.

t = 3 T, n is number of half lives = t / T = 3

<u>By using the decay law of radioactivity</u>

N / N0 = (1 / 2)^n

where

"N0" be the "initial amount"

"N" be the "amount left"

"n" be the "number of half-lives"

N / 36 = (1/2)^3

N / 36 = 1 / 8

N = 36 / 8 = 4.5 g

3 0
3 years ago
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A sprinter has a mass of 80 kg and a KE of 4000 J. What is the sprinter’s speed?
djyliett [7]
There you go.

Hope this helps!

8 0
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Para cargar un camión, se suele utilizar una tabla entre el contenedor y el suelo, con el fin de subir la carga, ya sea desplaza
stiks02 [169]

Answer:

A. No

B. si

Explanation:

A. El trabajo realizado en la carga es la energía potencial ganada por la carga al elevar la carga al nivel del camión y colocar la carga dentro del camión.

El trabajo realizado para elevar la carga W = m × g × h

Dónde;

m = masa de la carga

g = aceleración debido a la gravedad

h = Nivel de altura donde se coloca la carga en el camión

Por lo tanto, el trabajo realizado depende de la masa, m, de la carga y el nivel de altura, h, donde la carga se coloca en el camión y el trabajo realizado es el mismo para todos los métodos utilizados para colocar la carga en el camión

B. La ecuación para el trabajo realizado, W, también se puede escribir de la siguiente manera;

W = Fuerza, F × Distancia, D

De lo que tenemos;

F = W/D

Por lo tanto, cuando la mesa aumenta la distancia, como una rampa o un plano inclinado, la fuerza requerida disminuirá.

4 0
3 years ago
(III) A baseball is seen to pass upward by a window with a vertical speed of If the ball was thrown by a person 18 m below on th
Ghella [55]

Answer:

<em><u>Assuming that the vertical speed of the ball is 14 m/s</u></em> we found the given values:

a) V₀ = 23.4 m/s

b) h = 27.9 m

c) t = 0.96 s

d) t = 4.8 s

 

Explanation:

a) <u>Assuming that the vertical speed is 14 m/s</u> (founded in the book) the initial speed of the ball can be calculated as follows:  

V_{f}^{2} = V_{0}^{2} - 2gh

<u>Where:</u>

V_{f}: is the final speed = 14 m/s

V_{0}: is the initial speed =?

g: is the gravity = 9.81 m/s²

h: is the height = 18 m

V_{0} = \sqrt{V_{f}^{2} + 2gh} = \sqrt{(14 m/s)^{2} + 2*9.81 m/s^{2}*18 m} = 23.4 m/s  

b) The maximum height is:

V_{f}^{2} = V_{0}^{2} - 2gh

h = \frac{V_{0}^{2}}{2g} = \frac{(23. 4 m/s)^{2}}{2*9.81 m/s^{2}} = 27.9 m

c) The time can be found using the following equation:

V_{f} = V_{0} - gt

t = \frac{V_{0} - V_{f}}{g} = \frac{23.4 m/s - 14 m/s}{9.81 m/s^{2}} = 0.96 s

d) The flight time is given by:

t_{v} = \frac{2V_{0}}{g} = \frac{2*23.4 m/s}{9.81 m/s^{2}} = 4.8 s

         

I hope it helps you!    

3 0
3 years ago
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