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Alenkinab [10]
3 years ago
9

Which mass would have the greatest acceleration if the same unbalanced force was applied to each?

Physics
1 answer:
zubka84 [21]3 years ago
3 0
I don't know which masses you're looking at, so I can't describe it to you.
But whatever they look like, it would be the one with the smallest mass.
That's not necessarily the smallest one, just the one that weighs the least.
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In 1985 in San Antonio, Texas, an entire hotel building was moved several
sleet_krkn [62]

Answer:

The building was moved to a distance of, S = 510.2 m

Explanation:

Given data,

The mass of the building, m = 1.45 x 10⁶ kg

The work done to overcome the force of resistance, E = 1 x 10⁸ J

The force of resistance of the building, 2% of building weight

                                          Fₓ =  2 x 1.45 x 10⁶ x 9.8 / 100

                                               = 284200 N

The work done on the building,

                                    E = Fₓ · S

∴                                   S = E /  Fₓ

                                        = 1.45 x 10⁶ / 284200 N

                                        = 510.2 m

Hence, the building was moved to a distance of, S = 510.2 m

8 0
3 years ago
Suppose the green car was traveling at 0 miles the white car was traveling at 70 miles at the red car was trailing at 22 miles w
Elan Coil [88]

Answer:

The white car will cover the most distance every second.

Explanation:

The formula for the uniform speed of an object is given as follows:

s = vt

where,

s = distance covered by the object

v = speed of the object

t = time required

Now, if we assume time to be  constant at 1 s. Then the distance covered by each car will be directly proportional to the speed of the car. Hence, the car with the greatest speed will travel the greatest distance in 1 second.

We, have:

Speed of white car > Speed of red car > Speed of green car

<u>Therefore, the white car will cover the most distance every second.</u>

5 0
3 years ago
3)(20pts) Un barco invasor se encuentra a 560m de un puerto de defensa, el puerto tiene cañones que
Eduardwww [97]

a) Las balas de cañon disparadas desde el puerto deben tener una ángulo de 27.39° para que puedan impactar al barco, con una velocidad inicial de 82 m/s.

b) El tiempo de vuelo de las balas de cañon para alcanzar al barco que está a 560 m de distancia es de 7.69 s.

c) Sabiendo que el ángulo calculado en el inciso a) es para una distancia de 560 m, el barco debe estar a una distancia mayor para que las balas no lo alcancen.

a)

Podemos usar las ecuaciones de tiro parabólico para encontrar el ángulo que permita derribar al barco invasor.

x=\frac{v_{i}^{2}sin(2\alpha)}{g} (1)

Donde:

  • v(i) es la velocidad inicial del cañon (82 m/s)
  • α es el ángulo de tiro
  • g es la gravedad (9.81 m/s²)
  • x es el desplazamiento total (560 m)

Lo que debemos hacer es depejar α de la ecuación 1

sin(2\alpha)=\frac{xg}{v_{i}^{2}}

sin(2\alpha)=\frac{560*9.81}{82^{2}}

sin(2\alpha)=0.82

\alpha=\frac{sin^{-1}(0.82)}{2}

\alpha=27.39^{\circ}

Por lo tanto, el ángulo para que el cañón impacte en el barco es de 27.39 °.

b)

Sabemos que la componente de la velocidad en el eje x es constante, así que podemo usar la siguiente ecuación.

v_{x}=\frac{x}{t}

La componente x de la velocidad es V(x) = V(i)cos(α) y sabiendo la distancia total de 560 m, el tiempo será:

v_{i}cos(\alpha)=\frac{x}{t}

t=\frac{x}{v_{i}cos(\alpha)}

t=\frac{560}{82cos(27.39)}

t=7.69\: s

El tiempo total de vuelo de las balas de cañon es de 7.69 s.

c)

Sabemos que el ángulo calculado en el inciso a) es de 27.39 °, y ese valor fue calcualdo para una distancia de 560 m, por lo tanto el barco debe estar a una distancia mayor que esa para que las balas no lo alcancen.

Puedes encontrar más información sobre tiro parabólico aquí:

https://brainly.lat/tarea/3605927

Espero te haya sido de ayuda!

3 0
3 years ago
If 10. joules of work must be done to move 2.0 coulombs of charge from point A to point B in an electric field, the potential di
masya89 [10]
The equation for work (W) done by an electric field is:

W = qΔV

where q is the magnitude of the charge and ΔV is the potential difference. The question gives you W and q, so plug n' play to find ΔV:

10 = 2ΔV
ΔV = 5
8 0
3 years ago
1. How far does a 70 kg object move in meters (m) if it
fenix001 [56]

Answer:

Units of work would be equivalent to a Newton times a meter. ... An individual force does NOT do positive work upon an object if the object is moving at ... FALSE - Watt is the standard metric unit of power; Joule is the standard metric unit of energy. ... TRUE - A kg•m2/s2 is a mass unit times a speed squared unit, making it a ...

4 0
3 years ago
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