What is a homopolar motor?????)
2 answers:
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Answer:
m = 4.29 kg
Explanation:
Given that,
Mass of the object, m = 2.8 kg
Stretching in the spring, x = 0.018 m
Frequency of vibration, f = 3 Hz
Let m is the mass of the object that is attached to the spring. When it is attached the gravitational force is balanced by the force on spring. It is given by :
k = 1524.44 N/m
Since,
m = 4.29 kg
So, the mass that is attached to this spring is 4.29 kg. Hence, this is the required solution.
Answer:
Specific heat capacity, = 2.1J/g°C
Explanation:
Given the following data;
Mass = 250g
Quantity of heat = 34.125kJ = 34.125 * 1000 = 34125 Joules.
Change in temperature = 65.0∘C
To find the specific heat capacity;
Heat capacity is given by the formula;
Where;
Q represents the heat capacity or quantity of heat.
m represents the mass of an object.
c represents the specific heat capacity of water.
dt represents the change in temperature.
Making c the subject of formula, we have;
Substituting into the equation, we have;
Specific heat capacity, = 2.1J/g°C