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Helen [10]
3 years ago
14

The pressure at the top of a liquid

Physics
1 answer:
attashe74 [19]3 years ago
7 0

Answer:

\displaystyle \rho=1,024.74\ kg/m^3

Explanation:

Pressure

P=P_o+\rho gh

Where P_o is the atmospheric pressure, \rho is the density of the fluid, and h is the depth

The values are :

P_o= 1\ atm= 101,325\ Pa

P=261,000\ Pa

g=9.8\ m/s^2

h=15.9\ m

Solving the above equation for \rho

\displaystyle \rho=\frac{P-P_o}{gh}

\displaystyle \rho=\frac{261,000-101,325}{9.8(15.9)}

\displaystyle \rho=\frac{159,675}{155.82}

\boxed{ \rho=1,024.74\ kg/m^3}

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