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igor_vitrenko [27]
3 years ago
15

An athlete runs 200 m by running 100 m in a straight line and then turning around and running 100m back to the start point.

Physics
1 answer:
siniylev [52]3 years ago
6 0

Answer:

o

Explanation:

The athlete ran a total distance of zero because they ran 100m forward then turned around so they went back to their starting position

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After a model rocket reached its maximum height, it then took 5.0 seconds to return to the launch site. what is the approximate
kifflom [539]
Air resistance is ignored.
g = 9.8 m/s².
At maximum height, the vertical velocity is zero.

Let h =  the maximum height reached.
Let u =  the vertical launch velocity.

Because ot takes 5.0 seconds to reach maximum height, therefore
(u m/s) - (9.8 m/s²)*(5 s) = 0 
u = 49 m/s

The maximum height reached is
h = (49 m/s)*(5 s) - (1/2)*(9.8 m/s²)*(5 s)²
   = 122.5 m

Answer: 122.5 m
3 0
3 years ago
A technician services the carburetor, and then, performs a complete governor system adjustment. The governor system on the engin
madreJ [45]

Answer: Either of the two

Explanation:

Either of the two - the governed idle spring or the normal primary governor spring can be adjusted first.

The main function of the carburetor is to mix air with fuel.

5 0
3 years ago
What is the net charge of a metal ball if there are 21,749 extra electrons in it?
pickupchik [31]

Answer:

Q=3.47\times 10^{-15}\ C

Explanation:

Given that,

Number of extra electrons, n = 21749

We need to find the net charge on the metal ball. Let Q is the net charge.

We know that the charge on an electron is q=1.6\times 10^{-19}\ C

To find the net charge if there are n number of extra electrons is :

Q = n × q

Q=21749\times 1.6\times 10^{-19}\ C

Q=3.47\times 10^{-15}\ C

So, the net charge on the metal ball is 3.47\times 10^{-15}\ C. Hence, this is the required solution.

6 0
3 years ago
A solar collector is a device that absorbs ___________from the sun ?
Gekata [30.6K]

Answer:

SUNLIGHT OR SUNRAYS OR ENERGY OR HEAT

Explanation:

5 0
3 years ago
Read 2 more answers
A 1.50 cm high diamond ring is placed 20.0 cm from a concave mirror with radius of curvature 30.00 cm. The magnification is ____
Rama09 [41]

Answer:

Magnification, m = -0.42

Explanation:

It is given that,

Height of diamond ring, h = 1.5 cm

Object distance, u = -20 cm

Radius of curvature of concave mirror, R = 30 cm

Focal length of mirror, f = R/2 = -15 cm (focal length is negative for concave mirror)

Using mirror's formula :

\dfrac{1}{f}=\dfrac{1}{u}+\dfrac{1}{v}, f = focal length of the mirror

\dfrac{1}{v}=\dfrac{1}{f}+\dfrac{1}{u}

\dfrac{1}{v}=\dfrac{1}{-15}+\dfrac{1}{-20}

v = -8.57 cm

The magnification of a mirror is given by,

m=\dfrac{-v}{u}

m=\dfrac{-(-8.57)}{-20}

m = -0.42

So, the magnification of the concave mirror is 0.42. Thew negative sign shows that the image is inverted.

5 0
3 years ago
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