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podryga [215]
3 years ago
10

During an experiment, a toy car accelerates forward for a total time of 5 s. Which of the following procedures could a student u

se to determine the average net force exerted on the car during the 5 s that the car accelerates?
A) Use a meterstick and stopwatch to measure the distance the car travels for the 5 s.
B) Use a balance to determine the mass of the car. Use a motion sensor to measure the speed of the car at a time of 0 s and a time of 5 s.
C) Use a balance to determine the mass of the car. Use a meterstick to measure the distance the car travels for the 5 s.
D) Use a motion sensor to measure the speed of the car at a time of 0 s and a time of 5 s. Use a meterstick to determine the distance the car travels for 5 s.
Physics
1 answer:
levacccp [35]3 years ago
3 0

Answer: B

Explanation: The motion sensor will measure the speed (velocity) of the car. Since the mass of the car has been measured, we can use formulas to calculate the average force.

Average net force = mass × acceleration

The mass of the toy car is measured first and noted

To calculate the velocity,

the car starts from rest since the velocity is associated with the distance and time after 5s.

Acceleration = velocity/time

With that the acceleration can be found.

acceleration is defined as change in velocity per unit time.

Then,

Force = mass × acceleration

Option B is the best answer

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ivanzaharov [21]

Answer: Power is 200 W

Explanation: Power P = work done / time used.

P = W/t = mgh/t = 154 kg · 9.81 m/s²· 4 m / 30 s = 201 W

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A pump uses a piston of 15 cm diameter that moves at 2.0 cm/s as it pushes a fluid through a pipe. what is the speed of the flui
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The important point here is that volumetric flow rate in the pump and the pipe is the same.

Q = AV, where Q = Volumetric flow  rate, A = Cross sectional area, V = velocity

Q (pump) = (π*15^2)/4*2 = 353.43 cm^3/s
Q (pipe) = (π*(3/10)^2)/4*V = 0.071V

Q (pump) = Q (pipe)
0.071V = 353.43 => V = 5000 cm/s

Therefore, the flow  of water in the pipe is 5000 cm/s.
4 0
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What do each of the variables mean ? <br> F=__________ m=_________<br>a=___________<br>​
wariber [46]

Answer:

F = Force (Measured in Newtons, N), m = Mass (Measured in kilograms, kg), and a = acceleration (Measured in metres per second squared, m/s^{2}

Explanation:

This is Newton's Second Law!

Hope this helps!

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8 0
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Why centre of mass equal to centre of gravity
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Read 2 more answers
A closely wound search coil has an area of 3.21 cm2, 120 turns, and a resistance of 58.7 O. It is connected to a charge-measurin
Alexxx [7]

Answer:

The magnetic field in the System is 0.095T

Explanation:

To solve the exercise it is necessary to use the concepts related to Faraday's Law, magnetic flux and ohm's law.

By Faraday's law we know that

\epsilon = \frac{NBA}{t}

Where,

\epsilon  =electromotive force

N = Number of loops

B = Magnetic field

A = Area

t= Time

For Ohm's law we now that,

V = IR

Where,

I = Current

R = Resistance

V = Voltage (Same that the electromotive force at this case)

In this system we have that the resistance in series of coil and charge measuring device is given by,

R = R_c + R_d

And that the current can be expressed as function of charge and time, then

I = \frac{q}{t}

Equation Faraday's law and Ohm's law we have,

V = \epsilon

IR = \frac{NBA}{t}

(\frac{q}{t})(R_c+R_d) = \frac{NBA}{t}

Re-arrange for Magnetic Field B, we have

B = \frac{q(R_c+R_d)}{NA}

Our values are given as,

R_c = 58.7\Omega

R_d = 45.5\Omega

N = 120

q = 3.53*10^{-5}C

A = 3.21cm^2 = 3.21*10^{-4}m^2

Replacing,

B = \frac{(3.53*10^{-5})(58.7+45.5)}{120*3.21*10^{-4}}

B = 0.095T

Therefore the magnetic field in the System is 0.095T

3 0
3 years ago
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