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Anna71 [15]
3 years ago
10

If electrical current is moving through a horizontal wire toward your face, what direction is the induced magnetic field?

Physics
1 answer:
adoni [48]3 years ago
4 0

Answer:(b)

Explanation:

Given

Electric current flowing through the horizontal wire towards the observer's face.

The direction of the magnetic field is given by the right-hand thumb rule, i.e. place the thumb in the direction of current and the wrapping of fingers will give the direction of the magnetic field

the direction of the magnetic field will be counterclockwise as observed by an observer.

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Some radar systems detect the size and shape of objects such as aircraft and geological terrain. What is the frequency of such a
vova2212 [387]

Answer:

f=1.57\times 10^9\ Hz

Explanation:

Given that,

A system can detect objects as small as 19.1 cm i.e. 0.191 m. It is the wavelength.

We know that,

Frequency, f=\dfrac{c}{\lambda}

So,

f=\dfrac{3\times 10^8}{0.191}\\\\=1.57\times 10^9\ Hz

So, the frequency of such a system is equal to1.57\times 10^9\ Hz.

4 0
3 years ago
A block (mass m1) lying on a frictionless inclined plane is connected to a mass (mass m2) by a massless cord passing over a pull
azamat

Answer:

a) System aceleration:

  • a=\frac{g(m_2-m_1sin(\theta))}{m_1+m_2}

b) Direction of movement:

The block m_1 down the plane when the acceleration is negative. This occur when:

m_2-m_1sin(\theta)

The block m_2 up the plane when the acceleration is positive. This occur when:

m_2-m_1sin(\theta)>0

Explanation:

For the block m_1 the move direction is parallel (||) to the plane

\sum F_{||}=m_1a=T-sin(\theta)mg  (1)

For the block m_2  the move direction is vertical (y)

\sum F_y=m_2a=m_2g-T  (2)

Both blocks are connected with the same cable, therefore, the tension on the cable and the acceleration is the same for both.

Solving the equation 2 for T:

T=m_2g-m_2a   (3)

replacing (3) in the equation (1)

m_2g-m_2a- m_1gsin(\theta)=m_1a  (4)

solving (4) for a:

a=\frac{g(m_2-m_1sin(\theta))}{m_1+m_2}

8 0
3 years ago
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olga nikolaevna [1]

Answer:

5 is the tripoid stand

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4 0
3 years ago
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A bike traveling initially at a speed of 32 m/s accelerates
Vika [28.1K]

<u>We are given:</u>

Initial velocity (u) = 32 m/s

Acceleration (a) = 3 m/s²

Displacement (s) = 40 m

Final Velocity (v) = v m/s

<u>Solving for the Final Velocity:</u>

from the third equation of motion:

v² - u² = 2as

<em>replacing the variables</em>

v² - (32)² = 2(3)(40)

v² = 240 + 1024

v² = 1264

v = √1264

v = 35.5 m/s

Therefore, the velocity of the bike after travelling 40 m is 35.5 m/s

4 0
3 years ago
Match the term with its description.
Mrac [35]

A=Ion

B=pH

C=Acid

D=Alkaline

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3 years ago
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