9. 2,000
10. 3,200
11. 3,000
12. 1,800
13. 120
14. 125
15. 75
16. 30
17.
18.
I can't see the last two
The answer is: (2x+3) (3x+1)
Answer:
18ways
Step-by-step explanation:
Answer:
(3 ± √23 * i) /4
Step-by-step explanation:
To solve this, we can apply the Quadratic Equation.
In an equation of form ax²+bx+c = 0, we can solve for x by applying the Quadratic Equation, or x = (-b ± √(b²-4ac))/(2a)
Matching up values, a is what's multiplied by x², b is what's multiplied by x, and c is the constant, so a = 2, b = -3, and c = 4
Plugging these values into our equation, we get
x = (-b ± √(b²-4ac))/(2a)
x = (-(-3) ± √(3²-4(2)(4)))/(2(2))
= (3 ± √(9-32))/4
= (3 ± √(-23))/4
= (3 ± √23 * i) /4
<span>If i started a business making braclets for $2 and necklaces for $3 with a budget >200 what would be the inequality equation?
How would I graph
Solution:
let x= number of bracelets
y= number of necklaces
Thus, the equation would be:
</span>$2x+$3y>200
In graphing this equation, you just have to substitute any number for the values of x and y as long as when substituted, their sum is greater than 200
