In a closed ring a and in an open ring magnet are falling along the x axis of thrme ring .the current generated in a and b have
1 answer:
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We will solve this question using the second law of motion which states that force is directly equal to the product of mass and acceleration.
Where,
- F is force
- m is mass
- a is acceleration
In our case,
- F = ?
- m = 2500 kg
- a = 20m/s
<em>Thus, The force of 50000 Newton is required to accelerate a car of 2500 kg...~</em>
Answer:
The minimum compression is
Explanation:
From the question we are told that
The mass of the block is
The spring constant is
The coefficient of static friction is
For the the block not slip it mean the sum of forces acting on the horizontal axis is equal to the forces acting on the vertical axis
Now the force acting on the vertical axis is the force due to gravity which is mathematically given as
And the force acting on the horizontal axis is force due to the spring which is mathematically represented as
where x is the minimum compression to keep the block from slipping
Now equating this two formulas and making x the subject
substituting values we have