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Luda [366]
3 years ago
7

In a closed ring a and in an open ring magnet are falling along the x axis of thrme ring .the current generated in a and b have

directions
Physics
1 answer:
zhenek [66]3 years ago
8 0

Answer:

ALL AWNERS HERE

Explanation:

https://quizlet.com/449884025/test-3-physics-2-flash-cards/

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A parallel-plate capacitor with circular plates is charged by a constant current i. the radius a of the plates is much larger th
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1. The problem statement, all variables and given/known data A parallel-plate capacitor of capacitance C with circular plates is charged by a constant current I. The radius a of the plates is much larger than the distance d between them, so fringing effects are negligible. Calculate B(r), the magnitude of the magnetic field inside the capacitor as a function of distance from the axis joining the center points of the circular plates. 2. Relevant equations When a capacitor is charged, the electric field E, and hence the electric flux Φ, between the plates changes. This change in flux induces a magnetic field, according to Ampère's law as extended by Maxwell: ∮B⃗ ⋅dl⃗ =μ0(I+ϵ0dΦdt). You will calculate this magnetic field in the space between capacitor plates, where the electric flux changes but the conduction current I is zero.

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The theory of _____ suggests that the crust of the earth is divided into pieces and moves about on the upper mantle.
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A hollow glass prism doesnot cause the dispersion of light why?<br><br>Please HELP! Its urgent..​
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A mass is attached to an ideal spring. At time t = 0 the spring is at its natural length and the mass is given an initial veloci
JulijaS [17]

Answer:

t = T/4

Explanation:

The power delivered to the mass by the spring is work done by the spring per second.

P = \frac{dW}{dt}

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U = \frac{1}{2}kx^2

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U_{max} =\frac{1}{2}kA^2

So the first time the mass reaches to its amplitude can be found by the following equation of motion:

x = A\cos(\omega t + \phi)\\\phi = \pi/2 ~because ~at ~t= 0, ~ x = 0\\0 = A\cos(0 + \pi/2)\\x = A\cos(\omega t + \pi/2)

When the mass reaches the amplitude:

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\omega t = \pi/2

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\omega t = \pi/2\\\frac{2\pi}{T}t = \pi/2\\t = \frac{T}{4}

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