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FrozenT [24]
3 years ago
9

A proton moves from a location where V = 87 V to a spot where V = -40 V. (a) What is the change in the proton's kinetic energy?

J
(b) If we replace the proton with an electron, what is the change in kinetic energy? J
Physics
1 answer:
Art [367]3 years ago
6 0

Answer: a) 127 eV; b) there is no change of kinetic energy.

Explanation: In order to explain this problem we have to use the change of potentail energy ( conservative field) is equal to changes in kinetic energy. So for the proton ther move to lower potential then they gain kinetic energy from the electric field.  This means the electric force do work in this trayectory and then the protons increased changes its speed.

If we replace the proton by a electron we have a very different situaction, the electrons are located in a lower potental then  they can not move to higher potential  if any  external force does work on the system.

In resumem, the electrons do not move from a point with V=87 to other point with V=-40 V. The electric force point to high potential so the electrons  can not move to lower potential region (V=-40V).

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A ball of mass m falls vertically, hits the floor with a speed ui , and rebounds with a speed u f . what is the magnitude of the
Sholpan [36]

Answer:

Change of momentum = M (Vf - (-Vi))   where V represents the scalar speeds of the ball or

I = M (ui + uf)  and I is the impulse ΔM V = I     Force = Change in Momentum

5 0
2 years ago
When a resistor is connected to a 12 volt source, it draws a 185 mA current. what's the resistance? (I said 65 ohms). the same r
lyudmila [28]

Resistance-1 = (voltage-1) / (current-1) =

                       (12 V)  /  (0.185 A)  =  64.9 ohms .

Resistance-2 = (voltage-2) / (current-2) =
 
                           (90 V )  /  (1.25 A)  =  72 ohms .

The resistance changed between situation-1 and situation-2 .
How did that happen ?

Power = (voltage) x (current)

Power-1 = (12)  x  (0.185)  =  2.22 watts

Power-2 = (90)  x  (1.25)  =  112.5 watts

The poor resistor dissipated 51 times as much power during
the second trial.  It got all heated up, and its resistance went
through the roof.

Carbon resistors behave nicely and reliably, until you try to
toast bread or light up your bedroom with them.


8 0
3 years ago
Technician a says that a defective spark plug wire can cause an engine miss. technician b says that a defective spark plug can c
larisa86 [58]

Technician a says that a defective spark plug wire can cause an engine misfire. Technician b says that a defective spark plug can cause an engine misfire. In this case, both technicians are correct.

Technician A is correct, because, Bad spark plug wires can interfere with the electrical current flowing to the engine, making it difficult for the engine to complete the combustion cycle. An incomplete combustion cycle can cause an engine to misfire, also

Technician B is correct because, Dirty spark plugs can cause misfires as well as burned engine oil can prevent the plugs from creating the sparks needed to ignite the fuel after it goes into the cylinder. Old spark plugs can simply break and fail to produce a spark. A broken spark plug is a simple fix, just replace it.

To learn more about Engine misfire, here

brainly.com/question/28204007

#SPJ4

7 0
2 years ago
How are fission and fusion similar?
nirvana33 [79]

Answer:

C

Explanation:

Fusion and fission are similar in that they both release large amounts of energy. Nuclear fusion is a process in which two nuclei join to form a larger nucleus. Nuclear fission is a process in which a nucleus splits into two smaller nuclei.

8 0
2 years ago
If I wanted to generate a maximum emf of 20 V, what angular velocity (radians/sec, aka Hz) would be required given a circular co
sergij07 [2.7K]

Answer:

Angular velocity, \omega=35.36\ rad/s

Explanation:

It is given that,

Maximum emf generated in the coil, \epsilon=20\ V

Diameter of the coil, d = 40 cm

Radius of the coil, r = 20 cm = 0.2 m

Number of turns in the coil, N = 500

Magnetic field in the coil, B=9\times 10^{-3}\ T

The angle between the area vector and the magnet field vector varies from 0 to 2 π radians. The formula for the maximum emf generated in the coil is given by :

\epsilon=NBA\omega

\omega=\dfrac{\epsilon}{NBA}

\omega=\dfrac{20\ V}{500\times 9\times 10^{-3}\ T\times \pi (0.2\ m)^2}

\omega=35.36\ rad/s

So, the angular velocity of the circular coil is 35.36 rad/s. Hence, this is the required solution.

6 0
3 years ago
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