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FrozenT [24]
3 years ago
9

A proton moves from a location where V = 87 V to a spot where V = -40 V. (a) What is the change in the proton's kinetic energy?

J
(b) If we replace the proton with an electron, what is the change in kinetic energy? J
Physics
1 answer:
Art [367]3 years ago
6 0

Answer: a) 127 eV; b) there is no change of kinetic energy.

Explanation: In order to explain this problem we have to use the change of potentail energy ( conservative field) is equal to changes in kinetic energy. So for the proton ther move to lower potential then they gain kinetic energy from the electric field.  This means the electric force do work in this trayectory and then the protons increased changes its speed.

If we replace the proton by a electron we have a very different situaction, the electrons are located in a lower potental then  they can not move to higher potential  if any  external force does work on the system.

In resumem, the electrons do not move from a point with V=87 to other point with V=-40 V. The electric force point to high potential so the electrons  can not move to lower potential region (V=-40V).

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Zero field spot for opposite unequal charges
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The zero field location has to be on the line running between the two point charges because that's the only place where the field vectors could point in exactly opposite directions. It can't be between the two opposite charges because there the field vectors from both charges point toward the negative charge.

7 0
3 years ago
2 What are the products of the following general reaction? acid + base _______ + _______ A. salt; water B. oxygen; hydrogen C. w
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Salt + water because salt dissolved in water

8 0
3 years ago
Two people are standing on a 1.75-m-long platform, one at each end. The platform floats parallel to the ground on a cushion of a
Fiesta28 [93]

Answer:

0.05312 m

Explanation:

Given:

Length of platform L = 1.75 m

mass of ball m_b = 5.76 kg

mass of (people + platform) m_p = 184 kg

Initial Velocity of ball V_i,b = 0

Initial Velocity of ball (people + platform) V_i,p = 0

Find:

How far does the platform recoils to rest

Solution:

Using the conservation of momentum on ust before and after the ball was thrown P_i = P_f :

Where, P_i = 0 (initially at rest)

P_f = m_p*V_f,p + m_b * V_f,b

0 = m_p*V_f,p + m_b * V_f,b

V_f,p = - (m_b /m_p) * V_f,b

V_f,p = - (5.76 / 184)*V_f,b

V_f,p = - 0.0313*V_f,b   ....1

The time the ball is in air:

t = L / (V_f,b - V_f,p)   ...2

The distance that the platform moves d:

d = V_f,p *t  ....3

Substitute 2 into 3

d = V_f,p*L /(V_f,b - V_f,p)   .... 4

Solve 1 and 4 simultaneously :

d = - m_b*L / (m_b + m_p)

d = - 5.76*1.75 / (5.76 + 184)

d = -0.05312 m

The platform moves 0.05312 m to the opposite to which the ball is thrown.

5 0
3 years ago
A battery can provide a current of 1.80 A at 2.60 V for 6.00 hr. How much energy (in kJ) is produced?A battery can provide a cur
love history [14]

Answer:

The energy which is produced by a battery is 101.1 kJ.

Explanation:

The expression for the energy in terms of voltage, current and time is as follows;

E=VIt

Here, V is the voltage, I is the current and t is the time.

It is given in the problem that a battery can provide a current of 1.80 A at 2.60 V for 6.00 hr.

Calculate the energy of the battery.

E=VIt

Convert time from hour int seconds.

t=6 hr

t=(6)(60)(60)

t=21600 s

Put I= 1.80 A, V= 2.60 V and t= 21600 s in the expression of energy.

E=(2.60)(1.80)(21600)

E= 101.1 kJ

Therefore, the energy which is produced by a battery is 101.1 kJ.

4 0
3 years ago
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