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elixir [45]
3 years ago
7

You need to push a heavy box across a rough floor, and you want to minimize the average force applied to the box during the time

the box is being pushed. Which method of pushing results in the minimum average force being applied to the box?
A. Keep pushing the box forward at a steady speed.
B. Push the box forward a short distance, rest, then repeat until finished,
C. Push the box so that it accelerates forward at a constant rate.
Physics
1 answer:
Lemur [1.5K]3 years ago
4 0

Answer:A. Keep pushing the box forward at a steady speed.

Explanation: Frictional force is a resistant force which oppose the Movement of an object, frictional force can emanate from a rough surface.

When an object that is moving with a consistent force is opposed by the roughness of the surface through which it is moving,it will cause the object to continue to move with a reduced speed as it goes along.

WHEN YOU APPLY A CONSTANT FORCE ON A MOVING OBJECT THAT IS OPPOSED BY A ROUGH SURFACE IT WILL RESULT IN AN AVERAGE MINIMAL FORCE BEING APPLIED TO THE OBJECT.

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An object is thrown directly up (positive direction) with a velocity (vo) of 20.0 m/s and do= 0. How high does it rise (v = 0 cm
Anit [1.1K]

Answer:

The value of d is 20.4 m.

(C) is correct option.

Explanation:

Given that,

Initial velocity = 20 m/s

Final velocity = 0

We need to calculate the time

Using equation of motion

v = u+gt

Where, u = Initial velocity

v = Final velocity

Put the value into the formula

t = \dfrac{20}{9.8}

t= 2.04\ sec

We need to calculate the distance

Using equation of motion

s = ut+\dfrac{1}{2}gt^2

s=0+\dfrac{1}{2}\times9.8\times(2.04)^2

s=20.4\ m

Hence, The value of d is 20.4 m.

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3 years ago
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Korolek [52]

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Explanation:

The velocity V equation is distance d divided by time t:

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If we isolate t we will have:

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Answer:

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