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Sergeu [11.5K]
3 years ago
9

In egypt, the physiologic density is ______ greater than the arithmetic density [estimate value], because _______ [reason for di

fference].
Physics
1 answer:
topjm [15]3 years ago
4 0
<span>In Egypt, the physiologic density is 2580 persons per square kilometer greater than the arithmetic density which is 75, because most of the country's land is not suitable for agriculture.
The land which is suitable for agriculture is called arable land. when physiological density is larger than arithmetic density it means country less arable land.</span>
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The resistanceless inductor is connected across the ac source whose voltage amplitude is 24.5 V and angular frequency is 850 rad
timurjin [86]

Answer:

Part A 2.88 A, PART B 28.82 mA PART C  0.288 mA

Explanation:

We have given angular frequency \omega =850rad/sec

Voltage source has an amplitude of 24.5 V, So V= 24.5 volt

Part A

We have given inductance L=10^{-2}H

So inductive reactance X_L=\omega L=850\times 10^{-2}=8.5ohm

So current i=\frac{V}{X_L}=\frac{24.5}{8.5}=2.8823A

Part B

We have given inductance L=1 H

So inductive reactance X_L=\omega L=850\times 1=850ohm

So current i=\frac{V}{X_L}=\frac{24.5}{850}=28.82mA

Part C

We have given inductance L=100 H

So inductive reactance X_L=\omega L=850\times 100=85000ohm

So current i=\frac{V}{X_L}=\frac{24.5}{85000}=0.288mA

8 0
3 years ago
Who did not have experimental evidence to support his theory of the atom? Dalton Thomson Rutherford Democritus
Aloiza [94]

Democritus was the one who did not have experimental evidence to support his theory of the atom.

Answer: Option 4

<u>Explanation: </u>

The discovery of atoms were first stated by Democritus but due to the absence of any experimental proof, his statement was not noted as significant at that time.

After this, Dalton made the specific assumptions formulating some postulates for the atomic theory with proof. Then the cathode rays tube experiments performed by Thomson lead to the formation of plum pudding models of atom.

This is followed by Rutherford’s gold foil experiment discovering the presence of nucleus inside the atoms. So, Democritus first stated but due to absence of experimental evidences, his theory of atoms were not supported at that time.

3 0
3 years ago
What is the pressure at a depth of 15 cm brine of density 1.2/cm³? ​
Anna [14]

P = density × gravity acceleration × height

P = 1200 × 9.81 × 15/100

P = 1765.8

6 0
3 years ago
Read 2 more answers
5.00-kg particle starts from the origin at time zero. Its velocity as a function of time is given by v =6t^2 i + 2t j where v is
otez555 [7]

The concept of derivatives and integrals allows to find the results for the questions are the motion of a particle where the speed depends on time are:

       a)the position is:  r = 2 t³ i + t² j

       b) the position of the body on the y-axis is a parabola and on the x-axis it is a cubic function

       c) The acceleration is: a = 12 t i + 2 j

       d) the force is: F = 60 t i + 10 j

       e) the torque is:  τ = 40 t³ k^

       f) tha angular momentum is:  L = 4t³ - 6 t² k^

       g) The kinetic energy is: K = 2 m t² (9t² +1)

       h) The power is:   P = 2m (36 t³ + 2t)

Kinematics studies the movement of bodies, looking for relationships between position, speed and acceleration.

a) They indicate the function of speed.

        v = 6 t² i + 2t j

Ask the function of the position.   The velocity is defined by the variation of the position with respect to time

          v = \frac{dr}{dt}  

          dr = v dt

we substitute and integrate.

        ∫ dr = ∫ (6 t² i + 2t j) dt

        r - 0 = 6 \frac{t^3 }{3} \ \hat i + 2 \frac{t^2}{2 \ \hat j }  

       r = 2 t³ i + t² j

b) The position of the body on the y axis is a parabola and on the x axis it is a cubic function.

c) Acceleration is defined as the change in velocity with time.

           a = \frac{dv}{dt}  

           a = \frac{d}{dt} \ (6t^2 i + 2t j)  

           a = 12 t i + 2 j

d) Newton's second law states that force is proportional to mass times the body's acceleration.

          F = ma

          F = m (12 t i + 2 j)

          F = 5 12 t i + 2 j

          F = 60 t i + 10 j

e) Torque is the vector product of the force and the distance to the origin.

           τ = F x r

The easiest way to write these expressions is to solve for the determinant.

         \tau = \left[\begin{array}{ccc}i&j&k\\F_x&F_y&F_z\\x&y&z\end{array}\right]  

        \tau = \left[\begin{array}{ccc}i&j&k\\60t &10&0\\2t^3 &t^2&0\end{array}\right]  

       τ = (60t t² - 2t³ 10) k

       τ = 40 t³ k ^

f) Angular momentum

        L = r x p

        L =rx (mv)

        L = m (rxv)

The easiest way to write these expressions is to solve for the determinant.

       \left[\begin{array}{ccc}i&j&k\\2t^3 &t^2&0\\6t^2&2t&0\end{array}\right]  

    L = (4t³ - 6 t²) k

 

g) The kinetic energy is

            K = ½ m v²

            K = ½ m (6 t² i + 2t j) ²

            K = m 18 t⁴ + 2t²

            K = 2 m t² (9t² +1)

h) Power is work per unit time

           P = \frac{dW}{dt}dW / dt

The relationship between work and kinetic energy

           W = ΔK

     

          P = 2m \ \frac{d}{dt} ( 9 t^4 + t^2)

          p = 2m (36 t³ + 2t)

In conclusion with the concept of derivatives and integrals we can find the results for the questions are the motion of a particle where the speed depends on time are:

       a) The position is:  r = 2 t³ i + t² j

       b) The position of the body on the y-axis is a parabola and on the x-axis it is a cubic function

       c) The acceleration is: a = 12 t i + 2 j

       d) The force is: F = 60 t i + 10 j

       e) The torque is:  τ = 40 t³ k^

       f) The angular momentum is:  L = 4t³ - 6 t² k^

       g) The kinetic energy is: K = 2 m t² (9t² +1)

       h) The power is:   P = 2m (36 t³ + 2t)

Learn more here:  brainly.com/question/11298125

8 0
2 years ago
Read 2 more answers
In an elastic collision momentum is conserved as is
zzz [600]

In an elastic collision momentum is conserved as well as the kinetic energy

Explanation:

In physics, there are two types of collisions:

  • Elastic collision: in an elastic collision, the total momentum of the system is  conserved, and the total kinetic energy of the system is conserved as well. This is because there are no internal frictions acting on the system, so the energy is conserved. An example of elastic collision is (approximately) that occurring between two billiard balls.
  • Inelastic collision: in an inelastic collision, the total momentum of the system is conserved, while the total kinetic energy is not. In fact, due to the presence of internal frictions, part of the total energy is converted into thermal energy and sound during the collision, and therefore "wasted", so the final total kinetic energy is less than the initial one. An example of inelastic collision is the collision between two cars. The maximum amount of kinetic energy is lost when the two objects stick together after the collision; in this case, we talk about perfectly inelastic collision.

Therefore, the complete sentence is

In an elastic collision momentum is conserved as well as the kinetic energy

Learn more about collisions:

brainly.com/question/13966693#

brainly.com/question/6439920

#LearnwithBrainly

7 0
3 years ago
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