Answer:
(C) greater than zero but less than 45° above the horizontal
Explanation:
The range of a projectile is given by R = v²sin2θ/g.
For maximum range, sin2θ = 1 ⇒ 2θ = sin⁻¹(1) = 90°
2θ = 90°
θ = 90°/2 = 45°
So the maximum horizontal distance R is in the range 0 < θ < 45°, if θ is the angle above the horizontal.
Answer:
I'm pretty sure it's 37.5 joules of energy
Explanation:
hope this helps!
Answer:
Explanation:
Given
Velocity of point is given by 
To get maximum or minimum velocity differentiate v w.r.t t
so 
should be equal to zero
i.e. 
I think your answer would be DDT, but don't hold me to it
Answer:
a) acceleration
Explanation:
Acceleration is, by definition, the change of an object's velocity.
