1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lana66690 [7]
3 years ago
5

What is the pressure at a depth of 15 cm brine of density 1.2/cm³? ​

Physics
2 answers:
Anna [14]3 years ago
6 0

P = density × gravity acceleration × height

P = 1200 × 9.81 × 15/100

P = 1765.8

kari74 [83]3 years ago
6 0

From the question we have got;

  1. Height: 15 cm = 15/109m = 15 × 10-²
  2. Density: 1.2 cm³= 1.2g/cm³ = 1.2 × 10³ kg/m³
  3. Acceleration due to gravity:10m/s²

Pressure = ρgh

= 15 × 10-² × 1.2 × 10³ × 10

= 1800 Nm-²

You might be interested in
A concert loudspeaker suspended high off the ground emits 34 W of sound power. A small microphone with a 1.0 cm2 area is 44 m fr
rjkz [21]

Answer:

<u>Part A</u>

I = 1.4 mW/m²  

<u>Part B</u>

β = 91.46 dB

Explanation:

<u>Part A</u>

Sound intensity is the power per unit area of sound waves in a direction perpendicular to that area. Sound intensity is also called acoustic intensity.

For a spherical sound wave, the sound intensity is given by;

                                            I = \frac{P}{A}

                                            I = \frac{P}{4\pi r^{2}}

Where;

P is the source of power in watts (W)

I is the intensity of the sound in watt per square meter (W/m2)

r is the distance r away

Given:

P = 34 W,

A = 1.0 cm²

r = 44 m

The sound intensity at the position of the microphone is calculated to be;

                                     I = \frac{34}{4\pi (44)^{2}}

                                     I = \frac{34}{4\pi (44)^{2}}

                                     I = 0.0013975 W/m²

                                 ≈  I = 0.0014 W/m² = 1.4 × 10⁻³ W/m²

                                     I = 1.4 mW/m²

The sound intensity at the position of the microphone is 1.4 mW/m².

<u>Part B</u>

Sound intensity level or acoustic intensity level is the level of the intensity of a sound relative to a reference value.  It is a a logarithmic quantity. It is denoted by β and expressed in nepers, bels, or decibels.

Sound intensity level is calculated as;  

                                    β = 10log_{10}\frac{I}{I_{0}}  dB

Where,

β is the Sound intensity level in decibels (dB)

I is the sound intensity;

I₀ is the reference sound intensity;

By pluging-in, I₀ is 1.0 × 10⁻¹² W/m²

           ∴        β = 10log_{10}\frac{1.4 * 10^{-3} W/m^{2}}{1.0 * 10^{-12} W/m^{2}}

                      β = 10log_{10} (1.4 * 10^{9})

                      β = 91.46 dB

The sound intensity level at the position of the microphone is 91.46 dB.                

4 0
3 years ago
A chef fills 50ml container with 43.5 g of cooking oil. what is the density of the oil?
Rama09 [41]

Answer:

0.87 g per ml

Explanation:

D=M/V

43.5/50=0.87

3 0
3 years ago
A voltmeter is a device that measures _____.
olga55 [171]
A voltmeter<span> its </span>instrument<span> used for </span>measuring<span> electrical potential difference between two points in an electric circuit. </span>An ammeter<span> is a </span>measuring device<span> used to</span>measure<span> the electric current in a circuit.

</span>
5 0
3 years ago
Read 2 more answers
A fuel cell that is becoming very popular for cars runs on:
jok3333 [9.3K]
It runs on Hydrogen gas.

Actually, using hydrogen as a fuel is not new. We used to use it on air vehicle like air balloon. But back then, we still cannot figure out how to safely use this because Hydrogen exlodes rather easily
7 0
3 years ago
a female vocalist with a soprano voice can sing as high as 1000 hz. given that the speed of sound is 345 m/s what is the wavelen
Neporo4naja [7]

0.345 m.

<h3>Explanation</h3>

The wavelength is the distance that the wave travels in each cycle. The wave travels 345 meters in each second. Let the wavelength of this wave be \lambda. That's the distance the wave travels in one cycle.

The frequency of the sound wave is 1 000 Hz, meaning that there are 1 000 cycles in each second. The wave travels a distance of 1 000 wavelengths in one second. That would be a distance of 1,000\;\lambda.

From the speed of the wave, the wave travels 345 meters in one second. In other words,

1,000\;\lambda = 345.

\lambda = \dfrac{345}{1,000} = 0.345\;\text{m}.

To generalize:

\lambda = \dfrac{v}{f},

where

  • \lambda wavelength of the wave,
  • v the speed of the wave, and
  • f the frequency of the wave.
3 0
3 years ago
Other questions:
  • What is evaporation​
    8·2 answers
  • Which of the following is a vector quantity?
    9·1 answer
  • One piece of copper jewelry at 111°C has exactly twice the mass of another piece, which is at 28°C. Both pieces are placed insid
    5·1 answer
  • Kissa and Lily ran a race in gym class Lily was off balance so she did not start until 2 seconds had passed
    9·1 answer
  • A small lightbulb is 1.06 m from a screen. A) If you have a convex lens with 20 cm focal length, where are the two lens location
    12·1 answer
  • PLS Help
    9·1 answer
  • 1. A plane mirror has a<br>surface​
    14·2 answers
  • Ghfghfghfhghfhfghfhfhfhfghfgh
    8·2 answers
  • Place the following types of electromagnetic radiation in order from LOWEST energy
    14·1 answer
  • 4. What would you suggest we do to reduce our trade deficit?
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!