The difference between a need and a want gets blurry for some people because of:

The primary __________ cortex specializes in receiving signals from different parts of the body.

tiny-mole [99]

Answer:

C. somatosensory

Explanation:

The somatosensory cortex is located in the front area of the parietal lobe. It receives signals for various areas of the body registering sensory input.

3 0

3 years ago

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The legs of a weight lifter must ultimately support the weights he has lifted. A human tibia (shinbone) has a circular cross sec

Sergio039 [100]

Answer:

249003822308.05008 N

Explanation:

F = Force

$\sigma$ = Breaking stress of bone = 150 MPa

$d_2$ = Outer diameter = 3.6 cm

$d_1$ = Inner diameter = 2.3 cm

Area of the bone is assumed to be a hollow cylinder

$A=\dfrac{\pi}{4}(d_2^2-d_1^2)$

Stress is given by

$\sigma=\dfrac{F}{A}\\\Rightarrow F=\sigma A\\\Rightarrow F=\dfrac{150\times 10^6}{\dfrac{\pi}{4}(0.036^2-0.023^2)}\\\Rightarrow F=249003822308.05008\ N$

The maximum weight the person can lift without breaking his legs is 249003822308.05008 N

3 0

4 years ago

As a 2.0-kg object moves from (4.4 i + 5j) m to ( 11.6 i - 2j) m, the constant resultant force

aliina [53]

Answer:

v_f = 10.38 m / s

Explanation:

For this exercise we can use the relationship between work and kinetic energy

W = ΔK

note that the two quantities are scalars

Work is defined by the relation

W = F. Δx

the bold are vectors. The displacement is

Δx = r_f -r₀

Δx = (11.6 i - 2j) - (4.4 i + 5j)

Δx = (7.2 i - 7 j) m

W = (4 i - 9j). (7.2 i - 7 j)

remember that the dot product

i.i = j.j = 1

i.j = 0

W = 4 7.2 + 9 7

W = 91.8 J

the initial kinetic energy is

Ko = ½ m vo²

Ko = ½ 2.0 4.0²

Ko = 16 J

we substitute in the initial equation

W = K_f - K₀

K_f = W + K₀

½ m v_f² = W + K₀

v_f² = 2 / m (W + K₀)

v_f² = 2/2 (91.8 + 16)

v_f = √107.8

v_f = 10.38 m / s

3 0

3 years ago

The angular momentum of a flywheel having a rotational inertia of 0.200 kg · m2 about its central axis decreases from 3.80 to 0.

Bingel [31]

Answer:

14.3065 rad

-36.777 J

-28.29 W

Explanation:

$L_f$ = Final angular momentum = 0.6 kgm²/s

$L_i$ = Initial angular momentum = 3 kgm²/s

I = Moment of inertia = 0.2 kgm²

Torque is given by

$\tau=\dfrac{L_f-L_i}{t}\\\Rightarrow \tau=\frac{0.6-3.8}{1.3}\\\Rightarrow \tau=-2.46\ Nm$

$\theta=\omega_it+\dfrac{1}{2}\alpha t^2$

Initial angular speed is given by

$\omega_i=\dfrac{L_i}{I}$

Angular acceleration is given by

$\alpha=\dfrac{\tau}{I}$

$\theta=\omega_it+\dfrac{1}{2}\alpha t^2\\\Rightarrow \theta=\dfrac{L_it+\dfrac{1}{2}\tau t^2}{I}\\\Rightarrow \theta=\dfrac{3.8\times 1.3+\dfrac{1}{2}\times -2.46\times 1.3^2}{0.2}\\\Rightarrow \theta=14.3065\ rad$

The angle is 14.3065 rad

Work done is given by

$W=\tau \theta\\\Rightarrow W=-2.46\times 14.95\\\Rightarrow W=-36.777\ J$

The work done on the wheel is -36.777 J

Power is given by

$P=\dfrac{W}{t}\\\Rightarrow P=\dfrac{-36.777}{1.3}\\\Rightarrow P=-28.29\ W$

The power is -28.29 W

6 0

3 years ago

Find out the x-component and y-component of the following vectors:

Leno4ka [110]

Answer:

A = 15.0 cm; the vector is 30.00 north of west; = 15 cm N30W

Y - component = 7.5cm and X - component = -12.99 cm

B = 12.0 m; the vector is 55.00 north of east; = 12.0 m N55E

Y - component = 9.83 m and X - component = 6.88 m

C = 28.0 m/s; the vector is 40.00 south of west; = 28.0 m/s S40W

Y - component = - 17.998 m/s and X - component = - 21.448 m/s

D = 55.5 m/s2; the vector is 35.00 south of east; = 55.5 m/s² S35E

Y - component = - 31.835 m/s² and X - component = 45.466 m/s²

Explanation:

1. A = 15.0 cm; the vector is 30.00 north of west; = 15 cm N30W

Y - component = 15cm × sin30 = 7.5cm

X - component = -15cm × cos30 = -12.99 cm

2. B = 12.0 m; the vector is 55.00 north of east; = 12.0 m N55E

Y - component = 12.0 m × sin55 = 9.83 m

X - component =12.0 m × cos55 = 6.88 m

3. C = 28.0 m/s; the vector is 40.00 south of west; = 28.0 m/s S40W

Y - component = - 28.0 m/s × sin40 = - 17.998 m/s

X - component = - 28.0 m/s × cos40 = - 21.448 m/s

4. D = 55.5 m/s2; the vector is 35.00 south of east; = 55.5 m/s² S35E

Y - component = - 55.5 m/s² × sin35 = - 31.835 m/s²

X - component = 55.5 m/s² × cos35 = 45.466 m/s²

6 0

3 years ago

Read 2 more answers