Answer:
Speed is 1.962*10^-3m/s
Explanation:
Given that
Mass of proton==1.67*10^-27
Acceleration due to gravity (g)=9.81m/s^2
Angle of inclination A=90°
Charge (q)=1.6*10^-19
Magnetic field (B)=5*10^-5T
From lorentz force
It can be seen that
F=w =mg=qvBsinA
We're Velocity (v)=mg /qBsinA
V=1.67*10-27*9.81/1.6*10^-19*5*10^-5*sin90
V=1.962*10^-3m/s
First you need to find total mechanical energy which is kinetic energy+potential energy, or (1/2mv^2+mgh). Since there is no height, we can pretty much ignore the potential energy and just calculate the kinetic.
1/2mv^2=1/2(64)(3.4)^2= 369.92J. Since it says the speed is 0 at the end of the run, we can assume that all the mechanical energy was lost. Therefore, 369.92 J of energy was lost
Answer:
Vy = 80.5 [m/s]
Explanation:
In order to solve this problem we must use the Pythagorean theorem.
V = 90 [m/s]
The components are Vx and Vy:
Therefore:
where:
Vy = 2*Vx ; because one is twice of the other.
![90 = \sqrt{v_{x}^{2} +(2*v_{x})^{2} }\\ 90 =\sqrt{v_{x}^{2}+4*v_{x}^{2}} \\90 =\sqrt{5v_{x}^{2}} \\90=2.23*v_{x} \\v_{x}=40.25[m/s]](https://tex.z-dn.net/?f=90%20%3D%20%5Csqrt%7Bv_%7Bx%7D%5E%7B2%7D%20%20%2B%282%2Av_%7Bx%7D%29%5E%7B2%7D%20%7D%5C%5C%2090%20%3D%5Csqrt%7Bv_%7Bx%7D%5E%7B2%7D%2B4%2Av_%7Bx%7D%5E%7B2%7D%7D%20%5C%5C90%20%3D%5Csqrt%7B5v_%7Bx%7D%5E%7B2%7D%7D%20%5C%5C90%3D2.23%2Av_%7Bx%7D%20%5C%5Cv_%7Bx%7D%3D40.25%5Bm%2Fs%5D)
and the bigger vector is:
Vy = 40.25*2
Vy = 80.5 [m/s]
It has acceleration while it's in your hand and you're in the process of flinging it, but we don't know how much.
It has acceleration ... pretty big ... during the short time between hitting the first blade of grass and coming to rest in the dirt, at the end of its trip.
From the time it leaves your hand until it hits the grass on the way down, its has the same constant, continuous acceleration ... 9.8 m/s^2 downward, the acceleration of gravity.
The greatest acceleration is probably at the end of the trip, after it hits the grass, and its speed drops to zero in a tiny fraction of a second.
