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VikaD [51]
3 years ago
13

An object increases vert its velocity from 22M/S 236M/S and five seconds. What is the acceleration of the object

Physics
1 answer:
MariettaO [177]3 years ago
6 0

Answer:

\boxed {\boxed {\sf a=42.8 \ m/s^2}}

Explanation:

Acceleration can be found by dividing the change in velocity by the time.

a=\frac{v-u}{t} (<em>v </em>is the final velocity, <em>u</em> is the initial velocity, <em>t </em>is the time).

The velocity increased from 22 m/s to 236 m/s in 5 seconds. Therefore:

v=236 \ m/s\\u=22 \ m/s\\t= 5 \ s

Substitute the values into the formula.

a=\frac{236 \ m/s - 22 \ m/s}{5 \ s}

Subtract in the numerator.

  • 236 m/s-22 m/s=214 m/s

a=\frac{214 \ m/s}{5 \ s}

Divide.

a=42.8 \ m/s^2

The acceleration of the object is <u>42.8 meters per square second.</u>

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Vedmedyk [2.9K]

Answer:

6. Paula is correct. Think about buildings, buildings are constantly pushed by different forces like wind or gravity. The buildings aren’t moving but this doesn’t mean that they aren’t under force

Explanation:

6 0
2 years ago
An proton-antiproton pair is produced by a 2.20 × 10 3 MeV photon. What is the kinetic energy of the antiproton if the kinetic e
timama [110]

Answer:

K = 80.75 MeV    

Explanation:

To calculate the kinetic energy of the antiproton we need to use conservation of energy:

E_{ph} = E_{p} + E_{ap} = E_{0p} + K_{p} + E_{0ap} + K_{ap} = m_{0p}c^{2} + K_{p} + m_{0ap}c^{2} + K_{ap}

<em>where E_{ph}: is the photon energy, E_{0p} and E_{0ap}: are the rest energies of the proton and the antiproton, respectively, equals to m₀c², K_{p} and K_{ap}: are the kinetic energies of the proton and the antiproton, respectively, c: speed of light, and m₀: rest mass.</em>        

Therefore the kinetic energy of the antiproton is:    

K_{ap} = E_{ph} - m_{0p}c^{2} - K_{p} - m_{0ap}c^{2}

<u>The proton mass is equal to the antiproton mass, so</u>:

K_{ap} = E_{ph} - 2m_{0p}c^{2} - K_{p}  

K_{ap} = 2.20 \cdot 10^{3}MeV - 2(1.67 \cdot 10^{-27}kg)(3\cdot 10^{8} \frac {m}{s})^{2} - 242.85MeV

K_{ap} = 2.20 \cdot 10^{3}MeV - 2(1.67 \cdot 10^{-27}kg)(3\cdot 10^{8} \frac {m}{s})^{2}(\frac{1eV}{1.602 \cdot 10^{-19}J})(\frac{1 MeV}{10^{6}eV}) - 242.85MeV

K_{ap} = 80.75 MeV              

Hence, the kinetic energy of the antiproton is 80.75 MeV.

I hope it helps you!

3 0
3 years ago
An object has a velocity of 8 m/s and a kinetic energy of 480 J. What is the mass of the object? (Formula: )
andrezito [222]

Answer:

1/2mv^2 a(7.5 b(15 kg c(60 kg d(120 kg. nevermind i found the answer its (15 kg) because to solve for m its m= K2/v squared.

Explanation:

6 0
3 years ago
What is the product of an object’s mass and velocity? momentum net force kinetic energy
kaheart [24]

<u>Answer:</u>

The correct answer option is momentum.

<u>Explanation:</u>

Momentum is the product of an object's mass and velocity.

It is a term which describes the relationship between the mass of an object and the velocity of an object.

Momentum can be represented in the form of an equation as:

P = mv

where P is the momentum,

m is the mass of the object; and v is the velocity of that object.

6 0
3 years ago
Ben and Dan both weigh 600 N. They are doing pull-ups together. Each pull-up is 0.5 meters of distance. How much work do they ea
Natasha2012 [34]

Answer:

300 J

Explanation:

Work = (Force)*(distance) = 600 N ∗ 0.5 m = 300 J

5 0
2 years ago
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