Question

An object increases vert its velocity from 22M/S 236M/S and five seconds. What is the acceleration of the object

Answer 1

Answer:

$\boxed {\boxed {\sf a=42.8 \ m/s^2}}$

Explanation:

Acceleration can be found by dividing the change in velocity by the time.

$a=\frac{v-u}{t}$ (v is the final velocity, u is the initial velocity, t is the time).

The velocity increased from 22 m/s to 236 m/s in 5 seconds. Therefore:

$v=236 \ m/s\\u=22 \ m/s\\t= 5 \ s$

Substitute the values into the formula.

$a=\frac{236 \ m/s - 22 \ m/s}{5 \ s}$

Subtract in the numerator.

• 236 m/s-22 m/s=214 m/s

$a=\frac{214 \ m/s}{5 \ s}$

Divide.

$a=42.8 \ m/s^2$

The acceleration of the object is 42.8 meters per square second.