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Bumek [7]
2 years ago
6

Which of these compounds would you expect

Chemistry
1 answer:
Veseljchak [2.6K]2 years ago
6 0
ClBr, two nonmetals





Hope this helps you
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Approximately how many mineral species have scientists identified?
nekit [7.7K]
I think it’s 5000 because it says that their is over 4,124 valid species of minerals.
3 0
3 years ago
Read 2 more answers
A gas mixture contains twice as many moles of o2 as n2. addition of 0.200 mol of argon to this mixture increases the pressure fr
pantera1 [17]
Number of moles of oxygen = x

number of moles of nitrogen = y

x = 2y

initial pressure, p1 = 0.8 atm

final pressure, p2 = 1.10 atm

At constant volume and temperature p1 / n1 = p2 / n2

=> p1 / p2 = n1 / n2

n1 = x + y = 2y + y = 3y

n2 = 0.2 + 3y

=> p1 / p2 = 3y / (0.2 + 3y)

=> 0.8 / 1.10 = 3y / (0.2 + 3y)

=> 0.8 (0.2 + 3y) = 1.10 (3y)

0.16 + 2.4y = 3.3y

=> 3.3y - 2.4y = 0.16

=> 0.9y = 0.16

=> y = 0.16 / 0.9

=. x = 2*0.16/0.9 = 0.356

Answer: 0.356 moles O2
8 0
3 years ago
How many moles of aluminum oxide will be formed from 17 moles of aluminum reaction?
Ainat [17]

Answer:

8.5 moles of Al₂O₃ will formed

Explanation:

Given data:

Number of moles of Al = 17 mol

Number of moles of Al₂O₃ formed = ?

Solution:

Chemical equation:

4Al  +  3O₂     →     2Al₂O₃

Now we will compare the moles of Al₂O₃  with Al.

                  Al            :            Al₂O₃      

                   4            :              2

                   17           :            2/4×17 = 8.5 mol

8.5 moles of Al₂O₃ will formed.    

7 0
3 years ago
What is atoms in your own words
san4es73 [151]

Atom is the smallest indivisible particle of matter.

6 0
3 years ago
Gold forms face-centered cubic crystals. The atomic radius of a gold atom is 144 pm. Consider the face of a unit cell with the n
kipiarov [429]

Answer:

The length of an edge of this unit cell is 407.294 pm

Explanation:

Face centered cubic structure contains 4 atoms in each unit cell and 12 coordination number, occupying about 74% volume of the total cell. Face centered cubic structure is known for efficient use of space for atom packing.

To determine the edge length, a relationship between the radius of the atom and edge length is used.

X = R√8

Where;

X is the length of an edge of this unit cell

R is the radius of the gold atom = 144 pm = 144 X 10⁻¹² m

X = 144 X 10⁻¹²√8

X = 407.294 X 10⁻¹² m

X = 407.294 pm

Therefore, the length of an edge of this unit cell is 407.294 pm

8 0
3 years ago
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