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4 years ago

G brønsted-lowry proton transfer reaction, hydroxide functions as a/an ______.

Chemistry

2 answers:

Katen [24]4 years ago

6 0

In a bronsted lowry proton transfer reaction, the hydroxide functions as a/an <u>proton acceptor.</u>

Bases are the opposite of acids. Bases are basic since they take or accept protons. For example, a Hydroxide ion can accept a proton to form water.

san4es73 [151]4 years ago

3 0

Answer:

Base

Explanation:

A Brønsted-Lowry acid is simply a compound that supplies a hydrogen ion in a reaction. A Brønsted-Lowry base on the other hand, is a compound that accepts a hydrogen ion in a reaction.

Thus, the Brønsted-Lowry definitions of an acid and a base focus on the movement of hydrogen ions in a reaction, rather than on the production of hydrogen ions and hydroxide ions in an aqueous solution.

The hydroxide ion in these compounds accepts a proton (Hydrogen ion) from acids to form water: This means shydroxides functions as a base.

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Consider the following reaction:2NOBr(g) 2NO(g) + Br2(g)If 0.412 moles of NOBr(g), 0.678 moles of NO, and 0.224 moles of Br2 are

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Answer: $K_c=0.0587M$

Explanation: The given chemical reaction is:

$2NOBr(g)\rightleftharpoons 2NO(g)+Br_2(g)$

Equilibrium constant (Kc) in general is written as:

$K_c=\frac{[products]}{[reactants]}$

Note:- Coefficients are written as their powers

So, the Kc expression for the above reaction will be:

$K_c=\frac{[NO]^2[Br_2]}{[NOBr]^2}$

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$[NOBr]=\frac{0.412mol}{10.3L}$ = 0.040 M

$[NO]=\frac{0.678mol}{10.3L}$ = 0.0658 M

$[Br_2]=\frac{0.224mol}{10.3L}$ = 0.0217 M

Plug in the values in the equilibrium expression to calculate Kc.

$K_c=\frac{(0.0658M)^2(0.0217M)}{(0.040M)^2}$

$K_c=0.0587M$

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