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maks197457 [2]
3 years ago
12

For which gases does the ratio of PV to RT equal a constant?

Chemistry
1 answer:
Lisa [10]3 years ago
8 0
Ideal gasses (ideal gas law)
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I need this answer today help pls
umka2103 [35]

Answer:

A. 28 days

Explanation:

3 0
3 years ago
Read 2 more answers
A piece of black onyx was cut into a rectangular solid measuring 5.10 cm by 5.10 cm by 2.50 mm . What is the volume in cubic cen
Anika [276]

Answer:

Volume = 6.5025cm^3

Explanation:

Given

Initial Form: Onyx

Final Form: Rectangular Solid

Dimension of Solid = 5.10 cm by 5.10 cm by 2.50 mm

Required

Volume of the solid (in cm³)

The volume of a solid is calculated as thus;

Volume = Length * Width * Height

Assume the following;

Length = 5.10cm\\Width = 5.10cm\\Height = 2.50mm

The first thing to do is to convert the assumed height from mm to cm

Given that;

1mm = 0.1cm

This implies that

2.50mm = 2.50 * 0.1cm\\2.50mm = 0.25cm

Hence, the dimension of the solid in cm is:

Length = 5.10cm\\Width = 5.10cm\\Height = 0.25cm

The Volume is then calculated as;

Volume = 5.10cm* 5.10cm * 0.25cm

Volume = 6.5025cm^3

Hence, the volume of the rectangular solid is Volume = 6.5025cm^3

3 0
4 years ago
How many moles of gas were added to a balloon that started with 2.3 moles of gas and a volume of 1.4 l given that the final volu
Ierofanga [76]
<span>Ideal Gas Law is as follows: PV = nRT Now lets rearrange so we can get rid of some variables. V/n = RT/P Assuming temperature and pressure are the same (atmospheric pressure), we can get: PV/n = constant (k) Now since we are dealing with an initial state (2.3 moles, 1.4 liters) lets set that as V1 and n1 and the final state as V2 and n2 .V1/n1 = constant (k) V2/n2 = constant (k) Because the constant is the same (remember me making the assumptions above??) V1/n1 = V2/n2 now rearrangement: n1/V1/V2 = 1/n2 -1 = n2 Answer: 11.8 moles are in the final vessel. So to answer the question how much was ADDED, we need to subtract the initial mole number. 11.8 - 2.3 mols = 9.5 mols added</span>
6 0
4 years ago
Methylamine is a weak base for which kb is 4.4*10 −4 . calculate the ph of a solution made by dissolving 0.070 mol of methylamin
SVEN [57.7K]

Answer is: pH of methylamine is 11.78.<span>

</span>

Chemical reaction: CH₃NH₂(aq)+ H₂O(l) ⇌ CH₃NH₃⁺(aq) + OH⁻<span>(aq).
Kb(CH</span>₃NH₂) = 4,4·10⁻⁴.<span>
c</span>₀(CH₃NH₂) = n(CH₃NH₂) ÷ V(CH₃NH₂).

c₀(CH₃NH₂) = 0.070 mol ÷ 0.8 L = 0.0875 M.

c(CH₃NH₃⁺) = c(OH⁻) = x.

c(NH₂OH) = 0.0875 M - x; equilibrium concentration of methylamine.

Kb = c(CH₃NH₃⁺) · c(OH⁻) / c(CH₃NH₂).

0.00044 = x² /  (0.0875 M - x). 

Solve quadratic equation: x = c(OH⁻) = 0.00598 M.

pOH = -log(0.00598 M) = 2.22.

pH = 14 - 2.22 = 11.78.

4 0
4 years ago
When HCl(g) reacts with O2(g) to form H2O(g) and Cl2(g), 6.84 kcal of energy are evolved for each mole of HCl(g) that reacts. Wr
puteri [66]

Answer:

4HCl(g)+O2(g)= 2H2O(g)+2Cl2(g)

∆H=-27.36 kcal

Explanation:

The balanced equation shows that four molecules of HCl reacts with one molecule of Oxygen to give two molecules of water and two molecules of chlorine gas and evolves energy in a combustion reaction.

6 0
3 years ago
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