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fiasKO [112]
3 years ago
14

A space probe is traveling in outer space with a momentum that has a magnitude of 3.87 x 107 kg·m/s. A retrorocket is fired to s

low down the probe. It applies a force to the probe that has a magnitude of 1.41 x 106 N and a direction opposite to the probe's motion. It fires for a period of 9.55 s. Determine the momentum of the probe after the retrorocket ceases to fire.
Physics
1 answer:
Virty [35]3 years ago
6 0
Force = change in momentum / time, Force in opposite direction so negative
-1.41 x 10⁶ = (p₂ - 3.87 x 10⁷) / 9.55
p₂ = 2.52 x 10⁷ Ns
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The y component of a vector is 36, and the angle between the vector and the x axis is 27 what is the magnitude of the vector
xz_007 [3.2K]

Answer:

Magnitude of Vector = 79.3

Explanation:

When a vector is resolved into its rectangular components, it forms two vector components. These components  are named as x-component and y-component, they are calculated by the following formulae:

x-component of vector = (Magnitude of Vector)(Cos θ)

y-component of vector = (Magnitude of Vector)(Sin θ)

where,

θ = angle of the vector with x-axis = 27°

Therefore, using the values in the equation of y-component, we get:

36 = (Magnitude of Vector)(Sin 27°)

Magnitude of Vector = 36/Sin 27°

<u>Magnitude of Vector = 79.3</u>

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Answer:

\Delta t = 8 s

Explanation:

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