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vlabodo [156]
3 years ago
11

8.0 Kg of water is heater from 20°C to 40°C. The specific heat capacity of water is 4200 J/Kg °C. What is the energy supplied to

the water?
Physics
1 answer:
koban [17]3 years ago
6 0

Answer:

672000 J.

Explanation:

From the question,

q = cm(t₂-t₁)............................ Equation 1

Where q = heat energy supplied to the water, c = specific heat capacity of water, m = mass of water, t₂ = final temperature, t₁ = Initial temperature.

Given: m = 8.0 kg, c = 4200 J/kg°C, t₂ = 40°C, t₁ = 20°C

Substitute these values into equation 1

q = 8×4200×(40-20)

q = 8×4200×20

q = 672000 J.

Hence the energy suplied to the water is 672000 J.

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Answer:

Option (e)

Explanation:

If a mass attached to a spring is stretched and released, it follows a simple harmonic motion.

In simple harmonic motion, velocity of the mass will be maximum, kinetic energy is maximum and acceleration is 0 at equilibrium position (at 0 position).

At position +A, mass will have the minimum kinetic energy, zero velocity and maximum acceleration.

Therefore, Option (e) will be the answer.

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A 1.5-kilogram cart initially moves at 2.0 meters per second. It is brought to rest by a constant net force in 0.30 second. What
AnnZ [28]
Acceleration = (change in speed) / (time for the change)

Change in speed = (speed at the end) minus (speed at the beginning.

The cart's acceleration is

                               (0 - 2 m/s) / (0.3 sec)

                           = ( -2 / 0.3 ) (m/s²)  =  -(6 and 2/3) m/s² .

Newton's second law of motion says

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For this cart:      Force = (1.5 kg) x ( - 6-2/3 m/s²)

                                       = ( - 1.5 x 20/3 ) (kg-m/s²)

<span>                                       =      </span>- 10 newtons .

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6 0
3 years ago
The gauge pressure at the bottom of a cylinder of liquid is 0.30atm. The liquid is poured into another cylinder with twice the r
likoan [24]

Answer:

P_g' = 0.075 atm

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Gauge pressure at the bottom of the cylinder depends on the height of water in the cylinder

So here we can say that

P_g = \rho g h

now when liquid is filled to height "h" in base area "A" then gauge pressure of the liquid at the bottom is given as

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now we put the whole liquid into another cylinder with twice radius of the first cylinder

So area becomes 4 times

now by volume conservation we can say that if area is increased by 4 times then height of liquid will decrease by 4 times

so we have

h' = \frac{h}{4}

so gauge pressure is given as

P_g' = \frac{0.30}{4} = 0.075 atm

5 0
3 years ago
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