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3 years ago

The mass of an object with 500 J of kinetic energy moving with a velocity of 5 m/s is

Physics

1 answer:

Ann [662]3 years ago

4 0

40kg

Explanation:

Given parameters:

Kinetic energy = 500J

Velocity = 5m/s

Unknown:

Mass of the object = ?

Solution:

Kinetic energy is the energy due to motion of a body. It is expressed as:

K.E = $\frac{1}{2}$ mv²

m is the mass of the body

v is the velocity

To find the mass, make it the subject of the expression:

m = $\frac{2 K.E}{v[tex]^{2}$ }[/tex]

m = $\frac{2 x 500}{5[tex]^{2}$ }[/tex] = 40kg

Learn more:

Kinetic energy brainly.com/question/6536722

#learnwithBrainly

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Carly rode her bike for 300 meters in 30 seconds. One can calculate her

Nutka1998 [239]

Answer:

Explanation:

300 ÷ 30 = 10

Answer - 10

Hope this helps!!!

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2 years ago

the tallest man made structure At present is theWarszawa radio massin Warsaw Poland.This radio mast rises 646m above ground near

PtichkaEL [24]

All of that fluff at the beginning is interesting, but completely irrelevant
to the question. The question is just asking for the mass of an object
that weighs 3.6N on Earth.

Weight = (mass) x (acceleration of gravity)

3.6N = (mass) x (9.8 m/s²)

Divide each side
by 9.8 m/s : Mass = 3.6N / 9.8 m/s² = <em>0.367 kilogram</em> (rounded)

7 0

2 years ago

In a RLC circuit, a second capacitor is connected in parallel with the capacitor previously in the circuit. What is the effect o

Marrrta [24]

Answer:

<h2>Case i) if $\omega L > \frac{1}{\omega c}$ </h2><h2>So initially if the circuit is inductive in nature then its net impedance will decrease after this</h2><h2>Case ii) if $\omega L < \frac{1}{\omega c}$ </h2><h2>So initially if the circuit is capacitive in nature then its net impedance will increase after this</h2>

Explanation:

As we know that the impedance of the circuit is given as

$z = \sqrt{(\omega L - \frac{1}{\omega c})^2 + R^2}$

when we join another identical capacitor in parallel with previous capacitor in the circuit then we will have for parallel combination

$c_{eq} = c_1 + c_2$

so it is

$c_{eq} = 2c$

now we have

$z = \sqrt{(\omega L - \frac{1}{2\omega c})^2 + R^2}$

Case i) if $\omega L > \frac{1}{\omega c}$

So initially if the circuit is inductive in nature then its net impedance will decrease after this

Case ii) if $\omega L < \frac{1}{\omega c}$

So initially if the circuit is capacitive in nature then its net impedance will increase after this

7 0

3 years ago

Suppose that you lift four boxes individually, each at a constant velocity. The boxes have weights of 3.0 N, 4.0 N, 6.0 N, and 2

Alona [7]

Answer:

The vertical distance of weight 3.0 N = 4 m, vertical distance of weight 4.0 N = 3 m, vertical distance of weight 6.0 N = 2 m, vertical distance of weight 2.0 N = 6 m

Explanation:

Worked : work can be defined as the product of force and distance.

The S.I unit of work is Joules (J).

Mathematically it can be represented as,

W = F×d.................. Equation 1

d = W/F.............................. Equation 2

where W = work, F = force, d = distance.

<em>Given: W = 12 J</em>

(i) for the 3.0 N weight,

using equation 2

d = 12/3

d= 4 m.

(ii) for the 4.0 N weight,

d = 12/4

d = 3 m.

(iii) for the 6.0 N weight,

d = 12/6

d = 2 m.

(iv) for the 2.0 N weight,

d = 12/2

d = 6 m

Therefore vertical distance of weight 3.0 N = 4 m, vertical distance of weight 4.0 N = 3 m, vertical distance of weight 6.0 N = 2 m, vertical distance of weight 2.0 N = 6 m

8 0

3 years ago

A river flows at a velocity of 3 km/h relative to the riverbank. A boat moves downstream at a velocity of 15 km/h relative to th

Alexus [3.1K]

15+3=18km/hour
Think about it like this. The boat is going 15 faster than the river, and the river is going 3 faster than the bank, so the boat is going 18 faster than the river bank

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2 years ago