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inysia [295]
4 years ago
15

The mass of an object with 500 J of kinetic energy moving with a velocity of 5 m/s is

Physics
1 answer:
Ann [662]4 years ago
4 0

40kg

Explanation:

Given parameters:

Kinetic energy  = 500J

Velocity = 5m/s

Unknown:

Mass of the object = ?

Solution:

Kinetic energy is the energy due to motion of a body. It is expressed as:

          K.E = \frac{1}{2} mv²

  m is the mass of the body

  v is the velocity

 To find the mass, make it the subject of the expression:

         m = \frac{2 K.E}{v[tex]^{2}}[/tex]

          m =   \frac{2 x 500}{5[tex]^{2}}[/tex] = 40kg

Learn more:

Kinetic energy brainly.com/question/6536722

#learnwithBrainly

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A moving car has kinetic energy. If it speeds up until it is going four times faster than before, how much kinetic energy does i
Eva8 [605]
<h2>Ratio of final kinetic energy to initial kinetic energy is 16.</h2>

Explanation:

Kinetic energy , KE = 0.5mv²

Here car speeds up to four times the initial speed, we need to find ratio of final kinetic energy to initial kinetic energy.

Final speed = 4 x Initial speed = 4v

Initial KE = 0.5mv²

Final KE = 0.5 x m x (4v)²

Final KE = 16 x 0.5 x m x v²

Final KE = 16 x Initial KE

Ratio of final kinetic energy to initial kinetic energy is 16.

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3 years ago
How is my Engineering Project?
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To use Faraday's law for this problem, you will need to construct a suitable loop, around which you will integrate the electric
VikaD [51]

Answer:

a. xy

Explanation:

The Faraday's law of induction can be used to express the relationship between the electric field line integral and the magnetic flux rate change in a closed loop. In order to ensure that the relationship between the two variables is equivalent to zero, the integration should be conducted on the xy plane. The correct option is option a.

6 0
4 years ago
A student standing on a stationary skateboard tosses a textbook with a mass of mb = 1.35 kg to a friend standing in front of him
nataly862011 [7]

Answer:

a) u_c=0\ m.s^{-1}       &        m_c.v_c=m_b.v_b\times \cos\theta

b) v_c=0.0566\ m.s^{-1}

c) p_e=2.9218\ kg.m.s^{-1}

Explanation:

Given:

mass of the book, m_b=1.35\ kg

combined mass of the student and the skateboard, m_c=97\ kg

initial velocity of the book, v_b=4.61\ m.s^{-1}

angle of projection of the book from the horizontal, \theta=28^{\circ}

a)

velocity of the student before throwing the book:

Since the student is initially at rest and no net force acts on the student so it remains in rest according to the Newton's first law of motion.

u_c=0\ m.s^{-1}

where:

u_c= initial velocity of the student

velocity of the student after throwing the book:

Since the student applies a force on the book while throwing it and the student standing on the skate will an elastic collision like situation on throwing the book.

m_c.v_c=m_b.v_b\times \cos\theta

where:

v_c= final velcotiy of the student after throwing the book

b)

m_c.v_c=m_b.v_b\times \cos\theta

97\times v_c=1.35\times 4.61\cos28

v_c=0.0566\ m.s^{-1}

c)

Since there is no movement of the student in the vertical direction, so the total momentum transfer to the earth will be equal to the momentum of the book in vertical direction.

p_e=m_b.v_b\sin\theta

p_e=1.35\times 4.61\times \sin28^{\circ}

p_e=2.9218\ kg.m.s^{-1}

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The inner core is solid because it is made of very dense, or heavy, materials like iron and nickel. Even though it is very hot, these materials don't
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