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Alenkinab [10]
2 years ago
10

V70 Estimate the square root of the number below to the nearest tenth

Mathematics
2 answers:
Fiesta28 [93]2 years ago
6 0
8.4 hope that helps
nevsk [136]2 years ago
6 0
It’s 777777777777777222222222.000002020202020202202020202020
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Molly was curious if quadrilaterals ABCDABCDA, B, C, D and EFGHEFGHE, F, G, H were congruent, so she tried to map one figure ont
Novay_Z [31]

Answer:

The answer is below

Step-by-step explanation:

A transformation of a point is the movement of an point from an initial position to a new position. If an object is transformed, all the point of an object is transformed. Two figures are said to be congruent if they have the same shape and the measure of each of their sides are the same.

An object is congruent to another object if the object can be mapped to the other object when transformed.

6 0
3 years ago
Mr. Bojorquez has 32 homework papers and 28 tests to return. Ms. Williams has 104 homework papers and 98 tests to return. Find e
Aleks04 [339]

Answer:

No they are not equivalent

Step-by-step explanation:

The ratio for Ms.Bojorquez is 32:28 which simplified is 8:7

The ration for Ms.Williams is 104:98 which simplified is 52:49

These rations are not equivalent.

8 0
3 years ago
Read 2 more answers
Please help me mane fr
VMariaS [17]

Hi There!

Answer:

25x² - 4

Step-by-step explanation:

Solve: (5x - 2)²

Step 1: 25x² - 2²

Step 2: 25x² - 4

Hope This Helps :)

7 0
3 years ago
The altitude of a triangle is increasing at a rate of 1 cm/min while the area of the triangle is increasing at a rate of 2 cm^2/
VARVARA [1.3K]

Answer:

The base is decreasing at 2 cm/min.

Step-by-step explanation:

The area (A) of a triangle is given by:

A = \frac{1}{2}bh   (1)

Where:

b: is the base

h: is the altitude = 10 cm

If we take the derivative of equation (1) as a function of time we have:

\frac{dA}{dt} = \frac{1}{2}(\frac{db}{dt}h + \frac{dh}{dt}b)

We can find the base by solving equation (1) for b:

b = \frac{2A}{h} = \frac{2*120 cm^{2}}{10 cm} = 24 cm

Now, having that dh/dt = 1 cm/min, dA/dt = 2 cm²/min we can find db/dt:

2 cm^{2}/min = \frac{1}{2}(\frac{db}{dt}*10 cm + 1 cm/min*24 cm)

\frac{db}{dt} = \frac{2*2 cm^{2}/min - 1 cm/min*24 cm}{10 cm} = -2 cm/min    

         

Therefore, the base is decreasing at 2 cm/min.

               

I hope it helps you!  

7 0
2 years ago
POSSIBLE POINTS 125
Lena [83]

Answer:

$51.36

Step-by-step explanation:

48×7%

5 0
3 years ago
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