All categories

3 years ago

3(77/2-5/2y)+7y=111 the answer should be 9 but i don’t know the steps to get to it

Mathematics

1 answer:

inna [77]3 years ago

4 0

Answer:

see below

Step-by-step explanation:

Let's solve your equation step-by-step.

−

y)+7y=111

Step 1: Simplify both sides of the equation.

−

y)+7y=111

(3)(

)+(3)(

−5

y)+7y=111(Distribute)

231

−15

y+7y=111

(

−15

y+7y)+(

231

)=111(Combine Like Terms)

−1

231

=111

−1

231

=111

Step 2: Subtract 231/2 from both sides.

−1

231

−

231

=111−

231

−1

−9

Step 3: Multiply both sides by 2/(-1).

(

−1

)*(

−1

y)=(

−1

)*(

−9

)

y=9

Answer:

y=9

You might be interested in

You are setting up a zip line in your yard. You map out your yard in a coordinate plane. An equation of the line representing th

neonofarm [45]

Answer:

Distance is 6.7units to the nearest tenth.

Explanation:

To solve this problem, we the distance formula. And this is given as:

$D = \frac{|a x + b y + c|}{\sqrt{a^2 + b^2}}$

We were given the equation:

y = 2 x + 4

This can also be rewritten as:

y – 2 x – 4 = 0.

Therefore, a = -2, b = 1 and c = -4

Also, we were given the points:

(x, y) = (–4, 11)

Making use of the above formula for distance, we have:

$D = \frac{|-2\times -4 + 1\times 11 + -4|}{\sqrt{-2^2 + -4^2}}$

$D = \frac{15}{\sqrt{5}}$

D = 6.7units (to the nearest tenth)

8 0

3 years ago

Which are solutions of the equation x2 - 16 = 0? Check all that apply.

Maurinko [17]

Last one
Because you have to substitute it
So you do X times 2 - 16 = 0
And the only X that works is the last one cause 8 X 2 = 16 and 16 -16=0

5 0

3 years ago

What divided by five is seven

bagirrra123 [75]

The answer would be 35

5 x 7 = 35

5 0

3 years ago

Read 2 more answers

A source of information randomly generates symbols from a four letter alphabet {w, x, y, z }. The probability of each symbol is

koban [17]

The expected length of code for one encoded symbol is

$\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha\ell_\alpha$

where $p_\alpha$ is the probability of picking the letter $\alpha$ , and $\ell_\alpha$ is the length of code needed to encode $\alpha$ . $p_\alpha$ is given to us, and we have

$\begin{cases}\ell_w=1\\\ell_x=2\\\ell_y=\ell_z=3\end{cases}$

so that we expect a contribution of

$\dfrac12+\dfrac24+\dfrac{2\cdot3}8=\dfrac{11}8=1.375$

bits to the code per encoded letter. For a string of length $n$ , we would then expect $E[L]=1.375n$ .

By definition of variance, we have

$\mathrm{Var}[L]=E\left[(L-E[L])^2\right]=E[L^2]-E[L]^2$

For a string consisting of one letter, we have

$\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha{\ell_\alpha}^2=\dfrac12+\dfrac{2^2}4+\dfrac{2\cdot3^2}8=\dfrac{15}4$

so that the variance for the length such a string is

$\dfrac{15}4-\left(\dfrac{11}8\right)^2=\dfrac{119}{64}\approx1.859$

"squared" bits per encoded letter. For a string of length $n$ , we would get $\mathrm{Var}[L]=1.859n$ .

5 0

3 years ago

Please help me idk this ???

nydimaria [60]

Answer:

Step-by-step explanation:

16/100 = x / 400

Cross multiply:-

100x = 16*400

x = 6400 / 100

= 64

7 0

4 years ago

Read 2 more answers