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Zolol [24]
3 years ago
13

The speed of sound in air is 10 times faster than the speed of a wave on a certain string. The density of the string is 0.002kg/

m. The tension in the string is __________.
Physics
1 answer:
nata0808 [166]3 years ago
3 0

Answer:

The tension on the string is 2.353 N.

Explanation:

Given;

the speed of sound in air, v₀ = 343 m/s

then, the speed of sound on the string, v = 343 / 10 = 34.3 m/s

mass per unit length, m/l = μ = 0.002 kg/m

The speed of sound on the string is given as;

v = \sqrt{\frac{T}{\mu} } \\\\v^2 = \frac{T}{\mu} \\\\T = v^2 \mu

where;

T is the tension on the string

T = (34.3)²(0.002)

T = 2.353 N

Therefore, the tension on the string is 2.353 N.

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Answer:

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2 years ago
If the back of the truck is 1.3 m above the ground and the ramp is inclined at 22 ∘ , how much time do the workers have to get t
solong [7]
Refer to the diagram shown below.

Assume that
(a) The piano rolls down on frictionless wheels,
(b) Wind resistance is negligible.

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Answer:

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---> v = emf / [B d cos (A)]

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A = angle of rails with respect to the horizontal

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where R = resistance of the bar

Thus,

I = B d v cos (A) / R

Thus, the bar experiences a magnetic force of

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Thus, the component of this parallel to the incline is

F(B //) = F(B) cos(A) = B I d = B^2 d^2 v cos^2 (A) / R

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B^2 d^2 v cos^2 (A) / R = m g sin (A)

where m = the mass of the bar.

Solving for v,

v = [R m g sin (A) / B^2 d^2 cos^2 (A)]   [ANSWER, the constant speed, PART A]

******************************

v = [R m g sin (A) / B^2 d^2 cos^2 (A)]

Plugging in the units,

m/s = [ [ohm * kg * m/s^2] / [T^2 m^2] ]

Note that T = kg / (s * C), and ohm = J * s/C^2

Thus,

m/s = [ [J * s/C^2 * kg * m/s^2] / [(kg / (s * C))^2 m^2] ]

= [ [J * s/C^2 * kg * m/s^2] / [(kg^2 m^2) / (s^2 C^2)]

As J = kg*m^2/s^2, cancelling C^2,,

= [ [kg*m^2/s^2 * s * kg * m/s^2] / [(kg^2 m^2) / (s^2)]

Cancelling kg^2,

= [ [m^2/s^2 * s * m/s^2] / [(m^2) / (s^2)]

Cancelling m^2/s^2,

= [s * m/s^2]

Cancelling s,

=m/s   [DONE! WE SHOWED THE UNITS ARE CORRECT! ]

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