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madam [21]
4 years ago
13

James Prescott Joule demonstrated that work could generate heat using his churn. In order to truly demonstrate that energy is co

nserved, the next logical step would have been to convert that heat entirely back to work. why was this not done?
Physics
1 answer:
IceJOKER [234]4 years ago
6 0

Answer:

Heat can be converted into work as that is the principle on which steam turbines work and generate electricity. But in order to achieve the result we need to modify the apparatus in such a way that heat is extracted from the fluid whose temperature increases due to churning. This requires a modified setup which is different from the one used by Joule. The relationship that work can be converted into heat and vice versa both requires different apparatus to be accomplished as a machine can act as either as one that does work or one on which work can be done.

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MakcuM [25]

That's a pretty good intuitive definition of a <em>theory </em>.

3 0
3 years ago
Read 2 more answers
What electron configurations do atoms usually achieve by sharing electrons to form covalent bonds?
Pani-rosa [81]

Explanation: The atoms attain the configuration of inert gas by sharing electrons.

Lets take an example of HCl,

Atomic number of H is 1 and it has only 1 valance electron. whereas atomic number of chlorine is 17 and it has 7 valance electron.

When hydrogen atom combine with chlorine atom then they share electrons through covalent bonding in order to complete their octet.

According to figure,

Electronic configuration of H = 1

Electronic configuration of Cl = 2,8,7

Now, after share of electron

Electronic configuration of H = 2

Electronic configuration of Cl = 2,8,8

Hence, we can conclude that when atoms share electrons then their octet gets complete and atoms achieve noble gas electronic configuration.

7 0
3 years ago
An object has an emissivity of 0.725. At temperature T, it radicates heat at a rate of 10 W. What is its rate of heat radiation
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3 0
3 years ago
Can an electric field exist in a vacuum?
statuscvo [17]
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3 0
3 years ago
For the following questions, assume the wavelengths of visible light range from 380 nm to 760 nm in a vacuum. (a) What is the sm
Karolina [17]

Answer:

Explanation:

This is an interference exercise, which the case of constructive interference is described by the expression

          d sin θ  = m λ

in this case they indicate that we are in the ninth order (m = 9).

To be able to observe the pattern, the dispersion angle must be less than 90º

         

we substitute

           sin 90 = 1

           d = m  lang

           

let's calculate

           d = 9 λ

           d = 9 380 10⁻⁰

            d = 3.42 10⁻⁶  

           d2 = 9 760 10⁻⁹

           d2 = 6.84 10₋⁶

7 0
3 years ago
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