Answer:
ummmmmmmm
Explanation:
this might be some type of trick question bro lol
or someone tryna play with you if the teacher gave you this question bro she deserves to be fired
Answer:
a) W = 5360 J b) μ = 0.29
Explanation:
a) The work is, bold indicate vectors
W = F. d = F d cos T
W = 40 268 cos 60
W = 5360 J
b) The force of friction and opposes the movement of the body and if the speed of the body is constant implies that the external force in the direction of the movement is equal to the force of friction, or which work is the same
= -5360J
The negative sign is because the force of friction is contrary to the direction of movement
c) Let's write the work of the friction force
= fr d cos 180
fr = μ N
Since the body is on a horizontal surface, from Newton's second law on the Y axis
N-W = 0
N = W
fr = μ W
= - μ W d
μ = -
/ W d
μ = - (-5360) / 69 268
μ = 0.29
A2 = 16 m^2
Explanation:
Application of Pascal's law:
F1/A1 = F2/A2
Given:
F1 = 50 N. A1 = 1 m^2
F2 = 800 N A2 = ?
A2 = (F2/F1)A1 = (800 N/50 N)(1 m^2)
= 16 m^2
Answer:
a)
b)
.
Explanation:
Given that
Boyle's law
P V = Constant ,at constant temperature
a)
Given that


We know that for PV=C

Now by putting the values
PV= 50 x 0.106

Where P is in KPa and V is in 
b)
PV= C
Take ln both sides
So 
lnP + lnV =lnC ( C is constant)
By differentiating

So

When P= 50 KPa

It indicates the slope of PV=C curve.
It unit is
.
Or we can say that
.