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mote1985 [20]
3 years ago
10

Brian Lara is a cricketer playing in the field on the second day of a cricket test-match. He exerts a forward force on the 0.145

kg cricket ball, as he catches it, to bring it to rest from a speed of 38.2m/s. During the process, his hand recoils a distance of 0.135m. Determine the acceleration of the ball and the force which is applied to it by Brian Lara.
Physics
1 answer:
Blizzard [7]3 years ago
8 0

Answer:

a = -3984.6 m/s²

F = 577.76 N

Explanation:

The acceleration of the ball can be calculated by using the third equation of motion:

2as = v_f^2 - v_i^2\\

where,

a = acceleration of ball = ?

s = distance covered = recoil distance = 0.135 m

vf = final speed = 0 m/s

vi = initial speed = 38.2 m/s

Therefore,

2(0.135\ m)a = (0\ m/s)^2-(38.2\ m/s)^2\\

<u>a = -3984.6 m/s²</u>

here negative sign shows deceleration.

Now, for the force applied by Brian Lara will be equal in magnitude but opposite in direction of the force required to stop the ball:

F = -ma\\F = -(0.145\ kg)(-3984.6\ m/s^2)\\

<u>F = 577.76 N</u>

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A model used for the yield y of an agricultural crop as a function of the nitrogen level n in the soil (measured in appropriate
pychu [463]

<span>The maxima of an equation can be obtained by taking the 1st derivative of the equation then equate it to 0.</span>The value of N that result in best yield is when dy/dn = 0.

Taking the 1st derivative of the equation y=(kn)/(9+n^2) :<span>
</span>

By using the quotient rule the form of the equation is:<span>
y = g(n) / h(n) 
where:</span>

g(n) = kn    --->    g'(n) = k 

<span> <span>h(n) = 9 + n^2     --->    h'(n) = 2n </span>
dy/dn is defined as:
<span>dy/dn = [h(n) * g'(n) - h'(n) * g(n)] / h(n)^2 
dy/dn = [(9 + n^2)(k) - (kn)(2n)] / (9 + n^2)^2 
dy/dn = (9k + kn^2 - 2kn^2) / (9 + n^2)^2 
dy/dn = (9k - kn^2) / (9 + n^2)^2 
dy/dn = k(9 - n^2) / (9 + n^2)^2 

<span>Equate dy/dn = 0, then solve for n 
k(9 - n^2) / (9 + n^2)^2 = 0 
k(9 - n^2) = 0 
9 - n^2 = 0 
n^2 = 9 
n = sqrt(9) 
n = 3 

<span>Answer: The nitrogen level that gives the best yield of agricultural crops is 3 units.</span></span></span></span>

5 0
4 years ago
What affect would using a 12V car battery have on the operation of your circuit? (Do not try this.) What would happen to the cur
k0ka [10]

Answer:

Incomplete question

This is the completed question

If the resistor in the circuit had a larger resistance then the current would be then have to be proportionally smaller. Because the batteries each give off 1.5 volts then the current would have to be the variable that would change. What affect would using a 12V car battery have on the operation of your circuit? (Do not try this.) What would happen to the current? What would happen to the resistor?

Explanation:

Using ohms law as our basis

Ohms law state that, the voltage in an ohmic conductor is directly proportional to the current

V∝I

Resistance is the constant of proportionality

Then

V=iR

Since we want a relationship between current and resistance.

then, I=V/R

So, current is inversely proportional to Resistance

as the current increase the resistance reduce and as the current reduces the resistance increases.

a. So, increasing the voltage from 1.5V to 12V increases the current In the circuit because voltage Is directly proportional to I.

From ohms law

V=iR

When v =1.5V

I=1.5/R

When V increase to 12V

I=12/R

I.e, it increases by a factor of 8. Eight times it's initial value

b. Now, the resistance in the circuit is the constant of proportionality and it doesn't change in a given circuit expect when using a variable resistoa r like rheostat.

6 0
3 years ago
Which diagram correctly represents the electric field lines between two small electrically charged spheres?
hjlf

Answer:

hehe

Explanation:

6 0
3 years ago
Geronimo wants to move an object 12 meters. Calculate the net work done by the object with an applied force of 150 N and a frict
valina [46]

Answer:

1476 J

Explanation:

From the question,

Net Work done = Net force× distance moved by net force.

W' = (F-F')×d................... Equation 1

Where W' = Net work done, F = force applied, F' = Frictional force, d = distance moved.

Given: F = 150 N, F' = 37 N, d = 12 m

Substitute these values into equation 1

W' = (150-37)×12

W' = 123×12

W' = 1476 J.

hence the Net Work done by the object is 1476 J

4 0
3 years ago
A train travels 92 miles in 11 1/2 hours. what is its average speed in miles per hour?
Gnom [1K]
The answer is 8 mph.
5 0
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