When it's freezing outside, how does this insulation prevent the pipes from bursting?

Consider the word equation. Calcium hydroxide hydrochloric acid mc012-1. Jpg calcium chloride water Which is the corresponding f

dimulka [17.4K]

The corresponding formula equation is:

Upper Ca (upper OH) subscript 2 (s) plus 2 upper H upper Cl (l) right arrow upper Ca upper Cl subscript 2 (aq) plus 2 upper H subscript 2 upper O (l)

To obtain the word equation, we shall write out the balanced molecular equation. This is given below:

Calcium hydroxide => Ca(OH)₂

Hydrochloric => HCl

Calcium chloride => CaCl₂

Water => H₂O

Calcium hydroxide + Hydrochloric —> Calcium chloride + water

Ca(OH)₂ + HCl —> CaCl₂ + H₂O

There are 2 atoms of Cl on the right side and 1 atom on the left. It can be balance by writing 2 before HCl as shown below:

Ca(OH)₂ + 2HCl —> CaCl₂ + H₂O

There are a total of 4 atoms of H on the left side and 2 atoms on the right side. It can be balance by writing 2 before H₂O as shown below:

Ca(OH)₂ + 2HCl —> CaCl₂ + 2H₂O

Now, the equation is balanced.

Thus, the corresponding word equation is:

Upper Ca (upper OH) subscript 2 (s) plus 2 upper H upper Cl (l) right arrow upper Ca upper Cl subscript 2 (aq) plus 2 upper H subscript 2 upper O (l)

Learn more about balancing equation: brainly.com/question/15538713

8 0

2 years ago

Read 2 more answers

In the reaction of an acid with water, a hydronium ion forms

Nutka1998 [239]

Really, ionization takes place. It means the acid dissociates in water. Ionization is just a fancy way of saying dissociation. Always think easy.

Definition of IONIZATION: The process describing the dissociation of an acid in water.

If it ionizes or dissociates completely in water, then it shows that hydronium is a STRONG ACID. And if it ionizes partially, that shows hydronium is a WEAK ACID.

So, the answer will be choice B. by a process called ionization

4 0

4 years ago

For the reaction, a → b, the rate constant is 0.0208 m-1 sec-1. How long would it take for [a] to decrease from 0.100 to 0.0450

goldfiish [28.3K]

First, assume the order of the given reaction is n, then the rate of reaction i.e. $\frac{dx}{dt}=k\times[A]^{n}$

where, dx is change in concentration of A in small time interval dt and k is rate constant.

According to units of rate constant, the reaction is of second order.

$\frac{1}{[A]_{t}}-\frac{1}{[A]_{o}} = kt$ (second order formula)

Put the values,

$\frac{1}{0.04590 m}-\frac{1}{0.100 m} =0.0208 m^{-1}s^{-1} \times t$

$22.23 m -10 m =0.0208 m^{-1}s^{-1} \times t$

$\frac{12.23 m}{0.0208 m^{-1}s^{-1}} = t$

t= 587.9 s

Hence, time taken is 587.9 s

5 0

4 years ago

The thermal decomposition of N2O5 obeys first-order kinetics. At 45°C, a plot of ln[N2O5] versus t gives a slope of −6.40 × 10−4

finlep [7]

Answer:

1,080 min

Explanation:

A first order reaction follows the law:

$rate=k[A]$ , where [A] is the concentraion of the reactant A.

Equivalently:

$\dfrac{d[A]}{dt}=-k[A]$

Integrating:

$\dfrac{d[A]}{[A]}=-kdt$

$\ln \dfrac{[A]}{[A_o]}=-kt$

Half-life means [A]/[A₀] = 1/2, t = t½:

t½ = ln (2) / k

That means that the half-life is constant.

The slope of the plot of ln [N₂O₅] is -k. Then k is equal to 6.40 × 10⁻⁴ min⁻¹.

Thus, you can calculate t½:

t½ = ln(2) / 6.40 × 10⁻⁴ min⁻¹

t½ = 1,083 min.

Rounding to 3 significant figures, that is 1,080 min.

5 0

3 years ago

Cu + 2AgNO3 → Cu(NO3)2 + 2Ag

Eva8 [605]

Answer:

$m_{Ag}=135.8gAg$

$Y=88.4\%$

Explanation:

Hello there!

In this case, according to the described chemical reaction, it is possible to compute the theoretical mass of silver as mass via the 1:2 mole ratio of copper to silver and their atomic mass in the periodic table, in order to perform the following stoichiometric setup:

$m_{Ag}=40.gCu*\frac{1molCu}{63.55gCu}*\frac{2molAg}{1molCu}*\frac{107.87gAg}{1molAg}\\\\ m_{Ag}=135.8gAg$

Next, given the actual yield of 120 g, we compute the percent yield via:

$Y=\frac{120g}{135.8g}*100\%\\\\Y=88.4\%$

Regards!

4 0

3 years ago