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quester [9]
2 years ago
10

Given the equation F=9/5C +32 where C is the temperature in degrees Celsius and F is the corresponding temperature in degrees Fa

hrenheit, and the following ordered pairs: (5, F1), (30, F2)
Step 1 of 2: Compute the missing y values so that each ordered pair will satisfy the given equation.​
Mathematics
1 answer:
pentagon [3]2 years ago
7 0

Answer:

b

Step-by-step explanation:

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Anybody...Help!!!!!!!!!!!
Sloan [31]
Simple...

when they ask for the rate of change they ask for slope -->>

Using \frac{ y_{1} - y_{2} }{ x_{1} - x_{2} } to find the rate of change for (-3,0) and (-2,-5)

\frac{0--5}{-3--2}

\frac{0+5}{-3+2}

\frac{5}{-1}

m=-5 

Thus, your answer.


4 0
3 years ago
NEED HELP ASAP!!! The table shows the relationship between the number of bracelets made and the number of beads used:
Svetlanka [38]
Answer: 49
reason:
okay so basically to get to 3 to 5 you have to add 2. To get to 21 to 35 you need to add 14. To get to 5 to 7 you need to add 2, therefore adding 14 to 35. It's a pattern :)
5 0
2 years ago
Help please vkvvhghh
Rasek [7]

Answer:

g is 6 1/5

Step-by-step explanation:

8 0
3 years ago
In which set(s) of numbers would you find the number 0?
Harlamova29_29 [7]
Apparently it’s all of them
3 0
3 years ago
NO LINKS!!! Part 2: Find the Lateral Area, Total Surface Area, and Volume. Round your answer to two decimal places.​
slava [35]

Answer:

<h3><u>Question 7</u></h3>

<u>Lateral Surface Area</u>

The bases of a triangular prism are the triangles.

Therefore, the Lateral Surface Area (L.A.) is the total surface area excluding the areas of the triangles (bases).

\implies \sf L.A.=2(10 \times 6)+(3 \times 6)=138\:\:m^2

<u>Total Surface Area</u>

Area of the isosceles triangle:

\implies \sf A=\dfrac{1}{2}\times base \times height=\dfrac{1}{2}\cdot3 \cdot \sqrt{10^2-1.5^2}=\dfrac{3\sqrt{391}}{4}\:m^2

Total surface area:

\implies \sf T.A.=2\:bases+L.A.=2\left(\dfrac{3\sqrt{391}}{4}\right)+138=167.66\:\:m^2\:(2\:d.p.)

<u>Volume</u>

\sf \implies Vol.=area\:of\:base \times height=\left(\dfrac{3\sqrt{391}}{4}\right) \times 6=88.98\:\:m^3\:(2\:d.p.)

<h3><u>Question 8</u></h3>

<u>Lateral Surface Area</u>

The bases of a hexagonal prism are the pentagons.

Therefore, the Lateral Surface Area (L.A.) is the total surface area excluding the areas of the pentagons (bases).

\implies \sf L.A.=5(5 \times 6)=150\:\:cm^2

<u>Total Surface Area</u>

Area of a pentagon:

\sf A=\dfrac{1}{4}\sqrt{5(5+2\sqrt{5})}a^2

where a is the side length.

Therefore:

\implies \sf A=\dfrac{1}{4}\sqrt{5(5+2\sqrt{5})}\cdot 5^2=43.01\:\:cm^2\:(2\:d.p.)

Total surface area:

\sf \implies T.A.=2\:bases+L.A.=2(43.01)+150=236.02\:\:cm^2\:(2\:d.p.)

<u>Volume</u>

\sf \implies Vol.=area\:of\:base \times height=43.011193... \times 6=258.07\:\:cm^3\:(2\:d.p.)

8 0
2 years ago
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