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Bingel [31]
3 years ago
8

Platinum crystallizes with the face-centered cubic unit cell. The radius of a platinum atom is 139 pm. Calculate the edge length

of the unit cell and the density of platinum in g>cm3.
Chemistry
1 answer:
horrorfan [7]3 years ago
3 0

Answer:

Length = 393pm, Density = 21.3 g/cm^3.

Explanation:

From the question above, we have the following parameters or data which is going to aid in solving the above Question.

=> The radius of a platinum atom = 139 pm.

Therefore, the length can be calculated by making use of the formula given below:

Length = 2 √( 2r) = 2 × √ (2 × 139 × 10^-12m ) = 393 × 10^-10 m = 393pm.

The density can be calculated by making use of the chemical formula given below:

Density = mass ÷ volume = (195.064/ 6.02 × 10^23) ÷ (3.93 × 10^-10/ 10^-2) = 21.3 g/cm^3.

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Y = 57.15 − 0.5 X If Y equals 5 , what is X ?<br><br> Then is Y=3, what is X?
Fiesta28 [93]

When y equals 5, x is 104.3

When y equals 3 then x is 108.3

<em><u>Solution:</u></em>

<em><u>Given expression is:</u></em>

y = 57.15 - 0.5x

<h3><u>If y equals 5 what is x ?</u></h3>

Substitute y = 5 in given expression

5 = 57.15 - 0.5(x)

5 = 57.15 - 0.5x

0.5x = 57.15 - 5

0.5x = 52.15

Divide both sides by 0.5

x = 104.3

Thus when y equals 5, x is 104.3

<h3><u>If y = 3 what is x ?</u></h3>

Substitute y = 3 in given expression

3 = 57.15 - 0.5(x)

3 = 57.15 - 0.5x

0.5x = 57.15 - 3

0.5x = 54.15

Divide both sides by 0.5

x = 108.3

Thus when y equals 3 then x is 108.3

7 0
3 years ago
What sedimentary rock formed from sand deposits
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Explanation:

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Hydrochloric acid, or HCl, reacts with solid NaOH
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5 0
4 years ago
Read 2 more answers
How many amperes would be needed to produce 60.0 grams of magnesium during the electrolysis of molten mgcl 2 in 2.00 hours?
Shalnov [3]

Answer:

\boxed{\text{66.2 A}}

Explanation:

1. Write the equation for the reaction.

M_r:                 24.30

          MgCl₂ ⟶ Mg + Cl₂

m/g:                   60.0

2. Calculate the moles of Mg

Moles of Mg = 60.0 g Mg × (1 mol Mg/ 24.30 g Mg) = 2.469 mol Mg

3. Calculate the moles of electrons

Moles of electrons = 2.469 mol Mg × (2 mol electrons/1 mol Mg)

= 4.938 mol electrons

4. Calculate the number of coulombs

Q = 4.938 mol electrons × (96 485 C/1 mol electrons) = 476 500 C

5. Calculate the current required

Q  = It

I = Q/t

t = 2.00 h × (60 min/1h) × (60 s/1 min) = 7200 s

I = 476 500 C/7600 s= 66.2 C/s = 66.2 A

You need a current of \boxed{\textbf{66.2 A}}.

8 0
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