Answer:
31.31× 10²³ number of Cl⁻ are present in 2.6 moles of CaCl₂ .
Explanation:
Given data:
Number of moles of CaCl₂ = 2.6 mol
Number of Cl₂ ions = ?
Solution:
CaCl₂ → Ca²⁺ + 2Cl⁻
The given problem will solve by using Avogadro number.
It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.
The number 6.022 × 10²³ is called Avogadro number.
In one mole of CaCl₂ there are two moles of chloride ions present.
In 2.6 mol:
2.6×2 = 5.2 moles
1 mole Cl⁻ = 6.022 × 10²³ number of Cl⁻ ions
5.2 mol × 6.022 × 10²³ number of Cl⁻ / 1mol
31.31× 10²³ number of Cl⁻
Answer:
the lowest point of energy the the graph reaches
Each section would be 230 centimeters or 2.30 meters long.
<h3>Sectional division</h3>
The original wood pole is 12 meters long.
12 meters = 12 x 100 = 1200 centimeters
It is to be cut into 5 equal sections: 1200/5 = 240 centimeters
But each cut wastes 10 cm of the pole.
240 - 10 = 230 centimeters.
Thus, each section would be 230 centimeters or 2.30 meters long.
More on sectional divisions can be found here: brainly.com/question/15381501
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I think it is a radiation poisoning
