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melomori [17]
3 years ago
10

How many atoms of N are in 137.0 grams of N2O3?

Chemistry
2 answers:
sukhopar [10]3 years ago
4 0

can someone please help me with my chemistry

olasank [31]3 years ago
3 0

Answer: The number of N atoms in 137.0 g of N2O3 21.67 x 10∧23 atoms.

Explanation:

  • We must obtain the number of moles of the compound: (n = mass/molar mass), mass = 137.0 g and molar mass of N2O3 = 76.01 g/mol.
  • n = (137.0 g)/ (76.01 g/mol) = 1.80 mol.
  • It is necessary to determine the number of molecules of this sample.
  • Every mole contains Avagadro's number (6.02 x 10^23) of molecules.
  • The number of molecules = (6.02 x 10^23)(1.80) = 10.84 x 10∧23 molecules.
  • Every molecule of N2O3 contain 2 atoms of N.
  • The number of N atoms in 137.0 g of N2O3 = (10.84 x 10∧23 molecule) (2 atoms) = 21.67 x 10∧23 atoms.
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Answer:

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Explanation:

Complete Question

Soda are made fizzy by the carbon dioxide (CO₂) dissolved int he liquid. An amount of carbon dioxide equal to about 8.0 L of carbon dioxide gas at atmospheric pressure and 300.0 K can be dissolved can be dissolved in a 2-L bottle of soda. The molar mass of CO₂ IS 44 g/mol.

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Solution

Assuming that CO₂ is an ideal gas.

A) The amount of carbon dioxide in 2.0 L of soda bottle is equal to the amount of Carbon dioxide in about 8.0 L of carbon dioxide gas at atmospheric pressure and 300.0 K

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