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3 years ago

What is the main factor that prevents the growth of tropical plants in the northern part of the United States?

1 answer:

8 0

Hello,

I believe the leading factour that prevents the growth of tropical plants in the northern part of the United States is climate.

Faith xoxo

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Which of the following shows kinetic energy being converted into potential energy?

Komok [63]

B) a rock being tossed high into the air

3 0

3 years ago

Why are the parts of an atom that electrons occupy called electron clouds?

Anna [14]

Because it's literally impossible to tell exactly where something that size is
located at any particular time.

And that's NOT because it's so small that we can't see it. It's because any
material object behaves as if it's made of waves, and the smaller the object is,
the more the size of its waves get to be like the same size as the object.
When you get down to things the size of subatomic particles, it doesn't make
sense any more to try and talk about where the particle actually "is", and we only
talk about the waves that define it, and how the waves all combine to become a
cloud of probability of where the particle is.

I know it sounds weird. But that's the way it is. Sorry.

8 0

3 years ago

A sample of water with a mass of 1 gram freezes at 32°F. At what temperature will a 100-gram sample of water freeze?

valkas [14]

Answer:

3200°F

Explanation:

just add two zero's to the end

8 0

3 years ago

"A steel rotating-beam test specimen has an ultimate strength of 120 kpsi. Estimate the life of the specimen if it is tested at

MrRissso [65]

Answer:

life (N) of the specimen is 117000 cycles

Explanation:

given data

ultimate strength Su = 120 kpsi

stress amplitude σa = 70 kpsi

solution

we first calculate the endurance limit of specimen Se i.e

Se = 0.5× Su .............1

Se = 0.5 × 120

Se = 60 kpsi

and we know strength of friction f = 0.82

and we take endurance limit Se is = 60 kpsi

so here coefficient value (a) will be

a = $\frac{(f\times Su)^2}{Se}$ ......................1

put here value and we get

a = $\frac{(0.82\times 120)^2}{60}$

a = 161.4 kpsi

so coefficient value (b) will be

b = $-\frac{1}{3}log\frac{(f\times Su)}{Se}$

b = $-\frac{1}{3}log\frac{(0.82\times 120)}{60}$

b = −0.0716

so here number of cycle N will be

N = $(\frac{ \sigma a}{a})^{1/b}$

put here value and we get

N = $(\frac{ 70}{161.4})^{1/-0.0716}$

N = 117000

so life (N) of the specimen is 117000 cycles

7 0

3 years ago

The law of conservation of momentum states that...

Brums [2.3K]

Answer:

The momentum before is equal to the momentum after

Explanation:

It is equal and should level out in an equation.

4 0

3 years ago