Circumference C=2πr
<span>C=2π(1.5x10^8)=9.42x10^8 </span>
<span>In 365 Days there are 8760hr </span>
<span>V=distance/time </span>
<span>V=(9.42x10^8)/8760=107534.2km/hr </span>
Answer:
5.2941176471 kg or 5294.1 grams
Explanation:
g.p.e= mgh
g.p.e/gh=m
180j/10×3.4= m
180/34= m
5.2941 kg= m
Answer:
Part a)

Part B)

Part C)

Explanation:
Part A)
As we know that ball is hanging from the top and its angle with the vertical is 20 degree
so we will have






Part B)
Here we can use energy theorem to find the distance that it will move




Part C)
At terminal speed condition we know that




The ratio of the distance moved by the point at which the effort is applied in a simple machine to the distance moved by the point at which the load is applied, in the same time. In the case of an ideal (frictionless and weightless) machine, velocity ratio = mechanical advantage. Velocity ratio is sometimes called distance ratio.
Answer: A and B
Explanation:
A
The wavelength of both transverse and longitudinal waves is measured parallel to the direction of the travel of the wave.
Because wavelength is the distance between the two successful crest or trough.
B)
Amplitude of longitudinal waves is measured at right angles to the direction of the travel of the wave and represents the maximum distance the molecule has moved from its normal position.
Because amplitude is the measure of maximum displacement from the original position