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Andreyy89
3 years ago
9

g what are the bands of electromagneitc radiation and how are they related to energy frequency and wavelength

Physics
1 answer:
ch4aika [34]3 years ago
3 0

Answer:

The details of bands is given in explanation.

Explanation:

The electromagnetic waves are differentiated into different bands based upon their wavelengths and frequencies. The names of different bands are as follows:

1. Radio Waves

2. Micro Waves

3. Infra-red

4. Visible light

5. Ultra Violet

6. X-rays

7. Gamma Rays

<u>The frequency of every region or rays increases from 1 through 7</u>. The <u>energy of rays also increase from 1 through 7</u>. Since, the wave length is inversely related to energy and frequency, thus the <u>wavelength of rays decrease from 1 through 7</u>.

A detailed information of the bands is provided in the picture attached.

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A resistor is made out of a long wire having a length L. Each end of the wire is attached to a termina of a battery providing a
Len [333]

Answer:

B) 2I

Explanation:

The equation that relates voltage, current and resistance is V=RI.

The equation for the resistance of a material in terms of its resistivity, length and cross-sectional area is R=\frac{\rho L}{A}

In this case, the length is divided by 2 while keeping its resistivity (since it's the same material) and area, which means the resistance gets divided by 2. Then, looking at the equation I=V/R and keeping V constant, one deduces that since the resistance now is half than before then current now must be twice as before.

This is all intuitive in fact, cuting a homogeneous resistor in half and leaving the rest of the variables constant makes twice as easy for the electrons to cross the conductor, thus twice the current (one has to know that all the variables involved behave linearly, as the equations show).

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3 years ago
g The current through a 10 m long wire has a current density of 4 cross times 10 to the power of 6 space open parentheses bevell
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Answer:

The value is V  =  2 V

Explanation:

From the question we are told that

The length of the wire is l = 10 \ m

The current density is J =  4*10^6 \  A/m^2

The conductivity is \sigma  =  2*10^{7} \  S/m

Generally conductivity is mathematically represented as

\sigma  =  \frac{l}{RA}

Here R is the resistance which is mathematically represented as

R =  \frac{V}{I}

Here I is the current which is mathematically represented as

I  =  J * A

So

R =  \frac{V}{  J * A}

And

\sigma  =  \frac{l}{\frac{V}{  J * A} * A}

=> \sigma  =  \frac{l}{\frac{V}{J}}

=> V = \frac{l * J}{\sigma }

=> V = \frac{10  * 4*10^6}{2*10^{7}  }

=> V  =  2 V

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8 0
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