A change in velocity or a change in direction, or both! Hope this helps
Heat = m x c x Δθ
2000 = 2 x c x 5
Specific heat c = 200 J / Kg / C
Answer:
a)
The magnitude of the attractive force is 
b)
The magnitude of the repulsive force is 
c)
The magnitude of the net force is 
Explanation:
The explanation is shown on the first and second uploaded image
Answer:
a=2.304×10¹⁶m/s²
Explanation:
Given data
Distance d=2.5 nm=2,5×10⁻⁹m
Mass of proton m=1.6×10⁻²⁷kg
charge of proton q=1.6×10⁻¹⁹C
To find
acceleration a
Solution
Apply the Coulombs Law

Where k is coulombs constant (k=9×10⁹Nm²/C²)
q=q₁=q₂
r=d
So